Question

#. In a hot water heating system, there is a cylindrical pipe of length 14 m and diameter 5 cm.

Answer 1

Answer:

The total radiating surface is approximately 2.2 m^2

Step-by-step explanation:

Here, we want to get the total surface area of the cylindrical pipe

Firstly, we need the measurements to be uniform

If length is m, then diameter should be in meters too

That would be 5/100 = 0.05 m

Radius is half of the diameter

Mathematically, that’s 0.05/2 = 0.025 m

The formula for the total surface area is;

A = 2 * pi * r^2 + 2 * pi * r * h

A = (2 * 3.142 * 0.025^2) + (2 * 3.142 * 0.025 * 14)

A = 0.0039275 + 2.1994 =2.2033275

This is approximately 2.2 m^2