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IgorC [24]
3 years ago
5

How would you solve this? (2^-2/3^3) PLEASE EXPLAIN

Mathematics
2 answers:
REY [17]3 years ago
5 0

9514 1404 393

Answer:

  1/108

Step-by-step explanation:

Make use of the rule of exponents ...

  a^-b = 1/a^b

__

  \dfrac{2^{-2}}{3^3}=\dfrac{1}{(2^2)(3^3)}=\dfrac{1}{4\cdot 27}=\boxed{\dfrac{1}{108}}

__

If you type this expression into your calculator, you will get the repeating decimal ...

  \dfrac{2^{-2}}{3^3}=0.00\overline{925}=\dfrac{925}{99900}=\boxed{\dfrac{1}{108}}

Some calculators will convert this to a fraction for you.

nekit [7.7K]3 years ago
4 0

Answer: 1/108

Step-by-step explanation:

2^-2 is 1/4

3^3 is 27

1/4 / 27 = 1/108

Simple maths

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