Question

How would you solve this? (2^-2/3^3) PLEASE EXPLAIN

Answer 1

9514 1404 393

Answer:

  1/108

Step-by-step explanation:

Make use of the rule of exponents ...

  a^-b = 1/a^b

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  $\dfrac{2^{-2}}{3^3}=\dfrac{1}{(2^2)(3^3)}=\dfrac{1}{4\cdot 27}=\boxed{\dfrac{1}{108}}$

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If you type this expression into your calculator, you will get the repeating decimal ...

  $\dfrac{2^{-2}}{3^3}=0.00\overline{925}=\dfrac{925}{99900}=\boxed{\dfrac{1}{108}}$

Some calculators will convert this to a fraction for you.

Answer 2

Answer: 1/108

Step-by-step explanation:

2^-2 is 1/4

3^3 is 27

1/4 / 27 = 1/108

Simple maths