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3 years ago

Can someone Solve: 2x^2/3 = 8

Mathematics

1 answer:

Naddika [18.5K]3 years ago

8 0

Isolate the variable by dividing each side by factors that don't contain the variable.

x = 2 √ 3 , − 2 √ 3

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Can anyone help me please

7nadin3 [17]

Answer:

noqijauaajajajajabbaababbaa

7 0

2 years ago

The worlds two highest dams are both in Tajikistan. The rogue dam is 35 meters taller than the Nurek dam. together they are 635

galina1969 [7]

This is a sum and difference problem, with the equations
R-N=35
R+N=635
The solution of which is
R=(635+35)/2=335
N=(635-35)/2=300

In general, the sum and difference problem can be solved (most of the time mentally) using
Larger number = (sum + difference)/2
Smaller number = (sum - difference)/2

5 0

3 years ago

Let y = safe load in pounds and x = length in feet of a horizontal beam. A constant of proportionality k exists such that y=k/x

Contact [7]

Answer:

Option c. 30,000

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

Let

y ----> safe load in pounds

x ----> length in feet of a horizontal beam

we have

For $x=15\ feet, y=2,000\ pounds$

Remember that

$k=y*x$

substitute

$k=2,000*15=30,000$

7 0

2 years ago

Simply 36/1225 into the smallest fraction

Aleksandr-060686 [28]

Answer:

36/1225 is in the simplest form.

Step-by-step explanation:

The easiest way to simplify a fraction is to look at eachs prime factorization:

36 has the factors:

(1, 2, 3, 4, 9, 12, 18 , 36)

1225 has these factors:

(1, 5, 7, 25, 35, 49, 175, 245, 1225)

Now we look for a common factor greater than 1:

Hmm... there isn't one in these sequences! With that information in our belt, we now know that 36/1225 is in its simplest form.

4 0

3 years ago

The spring has a stiffness k=200n/m and is unstretched when the 25 kg block is at

g100num [7]

To solve this we are going to use the formula fro the force applied to a spring: $F=ks$
where
$k$ is the spring constant
$s$ is the extension

Since we know the $F=ma$ , we can replace that in our formula and solve for $a$ :
$ma=ks$
$a= \frac{ks}{m}$
where
$a$ is the acceleration
$k$ is the spring constant
$s$ is the extension
$m$ is the mass

We know for our problem that $k=200$ , $s=0.4$ , and $m=25$ . So lets replace those values in our formula to find $a$ :
$a= \frac{ks}{m}$
$a= \frac{(200)(0.4)}{25}$
$a=3.5 \frac{m}{s^2}$

We can conclude that the acceleration of the block when s=0.4m is $3.5 \frac{m}{s^2}$ .

7 0

2 years ago