How do i fix a name split in python

Using the flowchart diagram, identify the decision point of this solution. Identify vendors. Calculate amount due. Determine dat

andreev551 [17]

Answer:

answer is "is there an early pay discount"

Explanation:

3 0

4 years ago

Read 2 more answers

Having one password for all accounts is an easy way to remember passwords, but it will expose you to what risk?

Gwar [14]

<span>Having one password for all accounts is an easy way to remember passwords, but it will expose you to the risk of losing all of your accounts. If a person hacks one of your accounts, then they will have access to everything you own. </span>

3 0

3 years ago

Assume that sentence is a variable of type String that has been assigned a value. Assume furthermore that this value is a String

disa [49]

Answer:

//get the sentence from the user

Console.WriteLine("Enter your sentence");

//read the user information

string ans = Console.ReadLine();

//check if sentence ends with period

if(!ans.EndsWith("."))

{

Console.WriteLine("Sentence should end with period");

Environment.Exit(0);

}

//declear empty string firstword

string firstWord = "";

//split the requested sentence using single space character

string[] splitans = ans.Split(' ');

//assign firstword

firstWord = splitans[0];

//print out firstword

Console.WriteLine(firstWord);

Explanation:

The program uses c#.

5 0

3 years ago

How do i delete a question ?

seraphim [82]

i think we can't do that

7 0

3 years ago

Implement the RC4 stream cipher in C++. User should be able to enter any key that is 5 bytes to 32 bytes long. Be sure to discar

gladu [14]

Answer:

Explanation:

#include <iostream>

#include <string>

#include<vector>

using namespace std;

vector<int> permute(vector<int>, vector<int>);

string encrypt(vector<int>s1 , vector<int> t1, string p);

string decrypt(vector<int>s1, vector<int> t1, string p);

int main() {

string plaintext = "cryptology";

string plaintext2 = "RC4";

vector<int> S(256);

vector<int> T(256);

int key[] = { 1,2,3,6 };

int key2[] = { 5,7,8,9 };

int tmp = 0;

for (int i = 0; i < 256;i++) {

S[i] = i;

T[i] = key[( i % (sizeof(key)/sizeof(*key)) )];

}

S = permute(S, T);

for (int i = 0; i < 256 ;i++) {

cout << S[i] << " ";

if ((i + 1) % 16 == 0)

cout << endl;

}

cout << endl;

string p = encrypt(S, T, plaintext);

cout << "Message: " << plaintext << endl;

cout << "Encrypted Message: " << " " << p << endl;

cout << "Decrypted Message: " << decrypt(S, T, p) << endl << endl;

tmp = 0;

for (int i = 0; i < 256;i++) {

S[i] = i;

T[i] = key2[(i % (sizeof(key) / sizeof(*key)))];

}

S = permute(S, T);

for (int i = 0; i < 256;i++) {

cout << S[i] << " ";

if ((i + 1) % 16 == 0)

cout << endl;

}

cout << endl;

p = encrypt(S, T, plaintext2);

cout << "Message: " << plaintext2 << endl;

cout << "Encrypted Msg: " << p << endl;

cout << "Decrypted Msg: "<<decrypt(S, T, p) << endl << endl;

return 0;

}

string decrypt(vector<int>s1, vector<int> t1, string p) {

int i = 0;

int j = 0;

int tmp = 0;

int k = 0;

int b;

int c;

int * plain = new int[p.length()];

string plainT;

for (int r = 0; r < p.length(); r++) {

i = (i + 1) % 256;

j = (j + s1[i]) % 256;

b = s1[i];

s1[i] = s1[j];

s1[j] = b;

tmp = (s1[i] + s1[j]) % 256;

k = s1[tmp];

c = ((int)p[r] ^ k);

plain[r] = c;

plainT += (char)plain[r];

}

return plainT;

}

string encrypt(vector<int>s1, vector<int> t1, string p) {

int i = 0;

int j = 0;

int tmp = 0;

int k = 0;

int b;

int c;

int * cipher = new int [p.length()];

string cipherT;

cout << "Keys Generated for plaintext: ";

for (int r = 0; r < p.length(); r++) {

i = (i + 1) % 256;

j = (j + s1[i]) % 256;

b = s1[i];

s1[i] = s1[j];

s1[j] = b;

tmp = (s1[i] + s1[j]) % 256;

k = s1[tmp];

cout << k << " ";

c = ((int)p[r] ^ k);

cipher[r] = c;

cipherT += (char)cipher[r];

}

cout << endl;

return cipherT;

}

vector<int> permute(vector<int> s1, vector<int> t1) {

int j = 0;

int tmp;

for (int i = 0; i< 256; i++) {

j = (j + s1[i] + t1[i]) % 256;

tmp = s1[i];

s1[i] = s1[j];

s1[j] = tmp;

}

return s1;

}

6 0

3 years ago