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Bess [88]
3 years ago
15

Tourists from a tour bus were asked about places they visited during their stay in a city. The results are shown in the table. W

hat is the probability that a randomly selected tourist visited the museum, given that the tourist didn't visit the zoo?
Write the probability as a percent. Round to the nearest tenth if needed. SHOW ALL WORK!!!!!!

Mathematics
2 answers:
Elenna [48]3 years ago
6 0

Answer:

71.4 is the correct answer

MrRa [10]3 years ago
4 0
                                  Visited the museum        Did not visit the museum       total
Visited the zoo                      9                                        14                                    23
Didn't visit the zoo               5                                           2                                      7
Total                                     14                                          16                                    30           

<span>Probability that the tourist visited the museum but did not visit the zoo.
</span>
Using the table, 5 tourists visited the museum but not the zoo. 
The total number o tourists surveyed was 30.

Probability that the tourist visited the museum but didt not visit the zoo is

5/30 = 0.1666 or 16.67%
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Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
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In this problem:

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The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:

Z = -2:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2 = \frac{X - 3.5}{0.05}

X - 3.5 = -0.1

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Z = 2:

Z = \frac{X - \mu}{s}

2 = \frac{X - 3.5}{0.05}

X - 3.5 = 0.1

X = 3.6

The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

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