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3 years ago

HELP- PLS SOMEONE HELP ME SOB

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

5 0

Answer:

150 degrees

Step-by-step explanation:

Use the equation below to find the sum of all the interior angles in this polygon:

(number of sides - 2)*180

number of sides = 6

(6-2)*(180) = 4*(180) = 720

Now that you know the total sum, subtract all other angles to find x:

720 - 90 - 162 - 101 - 96 - 121 = 150

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Solving a quadratic equation by completing the square. De

postnew [5]

Answer:

x1, x2 = 7.73 , 4.27

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 12x + 33

a = 1 b = -12 c = 33

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (12 + √(-12^2 - (4 * 1 * 33))) / 2 * 1

x1 = (12 + √(144 - 132)) / 2

x1 = (12 + √12) / 2

x1 = (12 + 3.46) / 2

x1 = 15.46 / 2

x1 = 7.73

x2 = (12 - √(-12^2 - (4 * 1 * 33))) / 2 * 1

x2 = (12 - √(144 - 132)) / 2

x2 = (12 - √12) / 2

x2 = (12 - 3.46) / 2

x2 = 8.54 / 2

x2 = 4.27

8 0

3 years ago

Find r(x + 1) if r(x) = x3 + x + 1

suter [353]

Substitute x + 1 as x in the equation of the function:

$r(x)=x^3+x+1\\\\r(x+1)=(x+1)^3+(x+1)+1=x^3+3(x^2)(1)+3(x)(1^2)+1^3+x+1+1\\\\=x^3+3x^2+3x+x+2=x^3+3x^2+4x+2$

Used

$(a+b)^3=a^3+3a^3b+3ab^3+b^3$

7 0

3 years ago

Read 2 more answers

Pls help me with this

kvasek [131]

Answer:

1st one is positive

2nd one is negative

3rd one is negative

4th one is positive

Step-by-step explanation:

7 0

3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided. A.Solve a–9=20 B.Solve b–9&gt

Goryan [66]

Answer:

A) The value of a is 29.

B) The value of b is greater than 29.

C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

Step-by-step explanation:

Solving for Part A.

Given,

$a-9=20$

We have to solve for a.

$a-9=20$

By using addition property of equality, we will add both side by 9;

$a-9+9=20+9\\a=29$

Hence the value of a is 29.

Solving for Part B.

Given,

$b-9>20$

We have to solve for b.

$b-9>20$

By using addition property of inequality, we will add both side by 9;

$b-9+9>20+9\\b>29$

Hence the value of b is greater than 29.

Solving for Part C.

In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.

Solving for Part D.

The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.

5 0

3 years ago

What can k equal so that 2kx-3k<2x+4+3kx to have no solution

const2013 [10]

Answer: k = -2
solution: 2kx-3k<2x+4+3kx,
-3k-4<2x+3kx-2kx,
-3k-4<(k+2)x
Since this inequality has no solution, k = -2.

3 0

3 years ago