Answer:
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The metallurgist must use 5.538 pounds of an alloy with 39 % copper and 42.462 pounds of an alloy with 62 % copper.
<h3>How to calculate proportions of components associated to an alloy</h3>
Herein we must create a new alloy by using correct quantities of two alloys with distinct <em>copper</em> concentrations. All required information can be found by concept of <em>weighted</em> averages:
(62/100) · (48 lb) = (39/100) · x + (65/100) · (48 - x)
62 · 48 = 39 · x + 65 · 48 - 65 · x
3 · 48 = 26 · x
x = 5.538 lb
The metallurgist must use 5.538 pounds of an alloy with 39 % copper and 42.462 pounds of an alloy with 62 % copper.
To learn more on weighted averages: brainly.com/question/28053890
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In paraller connection you can calculate the equivlant resistqnce from the relation :
1/R(equi) = 1/R1 + 1/R2 + 1/R3
1/R(equi) = 1/20 +1/20 + 1/10
1/R(equi) = 0.05+0.05+0.1 = 0.2
so, R(equi) = 5 ohms
Answer:
4.55294117. If you want it rounded look below.
Step-by-step explanation:
-Rounded-
Hundredths:4.55
Tenth: 4.6
Thousandth: 4.553
Whole Number: 5
Hope this helps. :D
Let us suppose the given points are A (3, – 2) and B(– 3, – 4).
Let P and Q be the point of trisection. Therefore, we have
Trisection means is to divide a line segment into three equal parts. Hence, we can say that P divides AB in the ratio of 1:2 and Q divides in 2:1 .
Thus, coordinate of P is given by
Similarly the coordinate of Q is given by
Therefore, the coordinates of the point of trisection are