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2 years ago

6

Just give me the answer. Don’t need explanation... Write an equation of a cosine function with amplitude 3, a period of π, a pha

se shift of π/4 to the left, and translated 1 unit up.

1 answer:

laiz [17]2 years ago

8 0

This can be used y=3x+28y(20^2)

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Can i have some help on both of these questions for brainlist !!!!!!!!!!!

Nezavi [6.7K]

Answer:

B and A

Step-by-step explanation:

What I did for these problems is plug in the numbers listed for the x-value. For example, in your calculator you’d put; (1/2)^3 and that’d get you 1/8. Then, try it for 8^(2 - 3) which is also 1/8. So, (1/2)^3 = 8^(2 - 3).

The same process for the second problem. 16^(2(7/3) -3) = 4^((7/3) + 1). This should give you 101.59…

I hope this helps :)!

5 0

2 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

3 years ago

if Penelope's car has an average fuel consumption of 3 miles per gallon and she uses 9.5 gallons how far did she drive

KatRina [158]

Answer:

approximately 3.16 repeated

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

3x^2yz^3-9x^3y^2z^2+12x^2y^3z^2

PolarNik [594]

3×2=692047 82837=284749×2484r133.e9274

6 0

2 years ago

Which function represents a reflection of f(x) = 5(0.8)^x across the x-axis?

Vikki [24]

Answer: The correct option is second.

Explanation:

The given function is,

$f(x)=5(0.8)^x$

If we graph a function is f(x), then its coordinates is defined as (x,f(x)).

When the graph of f(x) is reflect across the x-axis, then the the x-coordinate remains the same and the sign of y-coordinate is changed. It means after reflecting across the x-axis,

$(x,y)\rightarrow(x,-y)$

The given given equation can be written as,

$y=5(0.8)^x$

To find the equation of the graph after reflection across the x-axis multiply both sides by -1.

$-y=-5(0.8)^x$

Because f(x)=y and g(x)=-y.

$g(x)=-5(0.8)^x$

Therefore the second option is correct and the graph of both function is given below.

6 0

3 years ago

Read 2 more answers