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Aleksandr [31]
3 years ago
13

Help ASAP.

Mathematics
1 answer:
denpristay [2]3 years ago
4 0

1.\\A(n)=-2\cdot5^{n-1}\\\\\text{Find the first, fourth, and eighth terms}\\\text{It means}\ A(1),\ A(4)\ \text{and}\ A(8).\\\\\text{Substitute}\ n=1,\ n=4\ \text{and}\ n=8\ \text{in}\ A(n):\\\\A(1)=-2\cdot5^{1-1}=-2\cdot5^0=-2\cdot1=-2\\\\A(4)=-2\cdot5^{4-1}=-2\cdot5^3=-2\cdot125=-250\\\\A(8)=-2\cdot5^{8-1}=-2\cdot5^7=-2\cdot78,125=-156,250\\\\\boxed{Answer:\ a)\ -2,\ -250,\ -156,250}.


2.\\a_1=-6,\ r=2\\\\\text{The formula of a n-th term of geometric sequence}\\\\a_n=a_1r^{n-1}\\\\\text{Substitute:}\\\\a_n=-6\cdot2^{n-1}=-6\cdot2^n\cdot2^{-1}=-6\cdot2^n\cdot\dfrac{1}{2}=-3\cdot2^n\\\\\boxed{Answer:\ A(n)=a_n=-3\cdot2^n}

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Savatey [412]

Answer:

For E, each angle is 60° because its an equilateral triangle.

F is 45° for x, 135° for y, lastly z is 22.5°

7 0
3 years ago
Please hurry find the measure of S
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Answer:

m∠S = 29.5

Explanation:

     Q

S \huge\boxed {\sf \triangle} R

In this triangle, QR = SQ, which means its an isosceles triangle, angle S and R is similar.

<u>Thus solve:</u>

m∠S = (180° - 121°)/2

m∠S = 29.5°

3 0
2 years ago
Read 2 more answers
2×+y=0, ×-y=6 what is the solution to this system of equations?
WITCHER [35]
2×+y=0,
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Add the 1st to the 2nd equation==> 3x +y-y=6+0==> 3x=6 & x=2

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3 years ago
3/100 mile in 3 seconds. how far in 1 minute
dlinn [17]

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60/100

Step-by-step explanation:

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3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
3 years ago
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