The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x
Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y
10y+ x-36=10x+y
Substitute y with 14-x
So we would get
10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5
Y=14-x
=14-5
=9
So the two digit number is
10y+x
=90+5
=95
Answer:
x f(x) g(x)
1 15 3
2 16 4
3 15 5
4 12 6
5 7 7
6 0 8
f(x) = g(x) when x = 5
Step-by-step explanation:
f(x) = -x² + 4x + 12
f(1) = -(1)² + 4(1) + 12 = 15
f(2) = -(2)² + 4(2) + 12 = 16
f(3) = -(3)² + 4(3) + 12 = 15
f(4) = -(4)² + 4(4) + 12 = 12
f(5) = -(5)² + 4(5) + 12 = 7
f(6) = -(6)² + 4(6) + 12 = 0
g(x) = x + 2
g(1) = 1 + 2 = 3
g(2) = 2 + 2 = 4
g(3) = 3 + 2 = 5
g(4) = 4 + 2 = 6
g(5) = 5 + 2 = 7
g(6) = 6 + 2 = 8
AED is adjacent to 44 and these two angles are supplementary, meaning they sum to 180 so...
AED=180-44=136°
Answer:
The value of x in the 2nd quadrant is always negative.
Step-by-step explanation:
There form four zones in the coordinate plane by placing the coordinate axes i.e. X-axis and Y-axis. The top right zone is called the 1st quadrant and 2nd, 3rd and 4th quadrants are the zones obtained by rotating in anticlockwise about the origin.
Since the 2nd quadrant is placed at the top left zone, so, we have to move in the negative x-direction along or parallel to the X-axis and to move in the positive y-direction along or parallel to the Y-axis.
Therefore, the value of x in the 2nd quadrant is always negative.
(Answer)
