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2 years ago

Which of the following could be the lengths of the sides of a 45°-45°-90° triangle?

Mathematics

2 answers:

I am Lyosha [343]2 years ago

5 0

Answer:

4/5/6= 6/4/5

Step-by-step explanation:

because that i have like with the mose cocative invous

Vikentia [17]2 years ago

4 0

Answer:

Step-by-step explanation: I just took the quiz.

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Can someone help me draw this out to visualize it?

Vedmedyk [2.9K]

Answer:

Solution given:

South distance :base[b]=80milea

East distance :perpendicular [p]=35miles

Now

<S=?

we have

$\tan( \alpha ) = \frac{p}{b} = \frac{35 }{80}$

$\alpha = \tan {}^{ - 1} ( \frac{7}{16} )$

$\alpha = 23.629°$ =24°

24° bearing should be taken from south airport to East airport.

3 0

3 years ago

What is the equation of the straight line that passes through (2,1) (5,7)

VMariaS [17]

Answer:

y = 2x - 3

Step-by-step explanation:

We are asked to find the equation of a straight line

Step 1: find the slope

( 2 , 1) ( 5 , 7)

x_1 = 2

y_1 = 1

x_2 = 5

y_2 = 7

Insert the values into the equation

m = (y_2 - y_1 )/ (x_2 - x _1)

m = (7 - 1 )/ (5 - 2)

m = 6/3

= 2

Step 2: substitute m into the equation

y = mx + c

y = 2x + c

Step 3 : sub any of the two points given into the equation

Let's use ( 2, 1)

x = 2

y = 1

y = 2x + c.

1 = 2(2) + c

1 = 4 + c

c = 1 - 4

c = -3

Step 4: sub c into the equation

y = 2x + c

y = 2x - 3

7 0

3 years ago

According to Professor Robinson, which of the following aspects of A Streetcar Named Desire can be said to reflect elements of T

natita [175]

The best and most correct answer among the choices provided by the first question is letter E which is all of the above.

On the other hand, the best and most correct answer among the choices provided by the second question is letter A which is rebirth and coming death.

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!

7 0

3 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

7 months ago

PLZ HELP IWILL GIVE BRAINLIESTTT

liq [111]

Answer:

Choice B

A = b x h

Step-by-step explanation:

In other words the area of a parallelogram is the base times height

8 0

2 years ago