Angle 1 is congruent to angles 3, 5, and/or 7

Angle 2 is congruent to angles 4, 6, and/or 8

Angle 5 is congruent to angles 7, 3 and/or 1

Angle 6 is congruent to angles 8, 4, and/or 2

Any of these answers could work for the blanks.

Angles 1 and 3, 2 and 4, 5 and 7, and angles 6 and 8 are congruent because they are vertical angles. They have the same vertex. Not all of these are congruent to each other if this doesn’t make sense. It’s only 1 is congruent to 3, 2 congruent to 4, etc.

Then you have your corresponding angles. These are ones like angles 2 and 6, then 1 and 5. You can also have 8 and 4, or 7 and 3 as corresponding angles

Transversal angles are different. This would be like angles 3 and 4, or 1 and 2. They are not always congruent. The only time they will be congruent is if they are both 90°. Transversal angles are essentially supplementary angles on the transversal line (the line that intersects through the set of parallel lines)

3 0

3 years ago

Please answer correctly !!!!!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!!

rodikova [14]

A+22°=90° (SUM OF COMPLEMENTRY ANGLES )

A=90°-22°

A=68° ANSWER.

5 0

3 years ago

Read 2 more answers

Please help me ...................

vova2212 [387]

Based on the chart on the left, you can see there are 2 dragonflies with the lengths of 3 1/4 inches. Therefore, 2 marks should be made over the 3 1/4 inches spot on the line plot.

Hope this helps

Brainliest would be appreciated

-AaronWiseIsBae

5 0

3 years ago

Which expressions represent the area of the entire shaded region, including the light and dark shading? select three options. 12

Alex Ar [27]

A triangle is a polygon. The total area of the figure can be represented by 12a, (6a+b), and 2b cm².

<h3>What is a triangle?</h3>

A triangle is a polygon with 3 sides and 3 vertices.

Since the area of a single triangle is a cm², and the shape is formed of 12 triangles, therefore, the area of the 12 triangles will be equal to,

$\text{Area of the complete figure} = 12 \times a = 12a\rm \ cm^2$

Given that the area of the complete dark portion is b cm², therefore, the area of the 6 triangles with a cm² of area each, and the black portion can be written as,

$\text{Area of the complete figure} = (6 \times a)+b = (6a+b)\rm \ cm^2$

As the dark portion also consists of 6 triangles with an area of a cm² each and the total sum of this dark area is b cm². Also, the light portion consists of 6 triangles with an area of a cm². Therefore, the total area can be written as,

$\text{Total area} = 6a+6a = b+b = 2b\rm\ cm^2$

Thus, the total area of the figure can be represented by 12a, (6a+b), and 2b cm².

Learn more about Triangles:

brainly.com/question/2773823

6 0

2 years ago