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Veronika [31]
3 years ago
10

WILL GIVE BRAINLIEST!!!

Mathematics
2 answers:
iren2701 [21]3 years ago
7 0

Answer:

A is the correct answer

Step-by-step explanation:

ryzh [129]3 years ago
6 0

Step-by-step explanation:

The shaded area shows the region where it is enclosed in sample space S but does not include the subset B.

Hence it is the complement of B. (A)

You might be interested in
Calculate a5 for the geometric sequence in which a1=1600 and the common ratio is 3/4.
Cloud [144]

Answer:

<em>a₅ = 506.25                   option a</em>

Step-by-step explanation:

Given that,

first term a₁ = 1600

common ratio (r) = \frac{3}{4}

We need to find the fifth term of the geometric progression

We know that the nth term formula

aₙ = a₁rⁿ-¹

where a₁ is first term and r is the common ratio

n is the number of terms

So, n = 5

a₅ = 1600 (\frac{3}{4})^{5-1}

a₅ = 1600*(\frac{3}{4}) ^{4}

a₅ = 1600*81/256

a₅ = \frac{2025}{4}

<em>a₅ = 506.25                   option a</em>

<em>That's the final answer</em>

8 0
3 years ago
Read 2 more answers
What is 723 divided by 31 , 1359 divided by and , 851 divided by 77 . Thank you!
shutvik [7]

Answer:

23.3 and 11.05

Step-by-step explanation:

hope it helped!

6 0
4 years ago
Asking easy questions so people can get points / will mark as brainliest (answer must be right)
baherus [9]
The answer to your question is 45 ✌️
8 0
3 years ago
WILL MARK BRAINLIEST
Burka [1]

Answer:

283.3%

Step-by-step explanation:

6.8 divided by 2.4 = 2.83333333333

2.8333 x 100 = 283.33

= 283.3%

5 0
3 years ago
Read 2 more answers
Let f(x) = 3x² + 1 and g(x) = x +4. <br><br> Find (f +g)(x) <br><br> and (f -g)(x).
Artist 52 [7]

Answer:

(f + g)(x) = 3x² + x + 5

(f - g)(x) = 3x² - x - 3

Step-by-step explanation:

(f + g)(x) → f(x) + g(x) → <u>3x² + 1</u> + <u>x + 4</u>

Combine like terms and you get: 3x² + x + 5

(f - g)(x) → f(x) - g(x) → <u>3x² + 1</u> - (<u>x + 4</u>)

Remember to distribute the neg. everything in the parentheses. Combine like terms and you get: 3x² - x - 3

6 0
2 years ago
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