Complete the point-slope equation of the line through (-4,8) and (4,4)

Mathematics

2 answers:

mixer [17]3 years ago

4 0

Slope formula - (y² - y¹) / (x² - x¹)

(-4, 8) (4, 4)

x¹ = -4

x² = 4

y¹ = 8

y² = 4

4 - 8 = -4

4 - - 4 = 8

Two negatives equal a positive

Simplify -4/8 = -1/2

Answer - -1/2

Hope this Helps!!

S_A_V [24]3 years ago

3 0

Answer:

y-4= -1/2(x-4)

Step-by-step explanation:

First you have to find the slope to write it in point slope

to do this you find change in Y over change in X

From -4 to 4 is postivite 8 and from 8 to 4 its -4

Now you do -4 divided by 8 and get -0.5 or -1/2 for slope now pick one of the points and put it in the formula y-y1=m(x-x1)

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Answer:

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3 years ago

Scores on the GRE (Graduate Record Examination) are normally distributed with a mean of 513 and a standard deviation of 82. Use

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Answer:

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4 years ago

Express the complex number in trigonometric form. -6 + 6 square root of 3 i ?

bagirrra123 [75]

$\bf \begin{array}{clclll}
-6&+&6\sqrt{3}\ i\\
\uparrow &&\uparrow \\
a&&b
\end{array}\qquad 
\begin{cases}
r=\sqrt{a^2+b^2}\\
\theta =tan^{-1}\left( \frac{b}{a} \right)
\end{cases}\qquad r[cos(\theta )+i\ sin(\theta )]\\\\
-------------------------------\\\\$

$\bf r=\sqrt{(-6)^2+(6\sqrt{3})^2}\implies r=\sqrt{36+(6^2\cdot 3)}\implies r=\sqrt{144}
\\\\\\
r=12\leftarrow 
\\\\\\
\theta =tan^{-1}\left( \frac{6\sqrt{3}}{-6} \right)\implies \theta =tan^{-1}\left( -\sqrt{3}\right)\implies \theta =
\begin{cases}
\frac{2\pi }{3}\leftarrow \\
\frac{5\pi }{3}
\end{cases}$

now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.

thus $\bf 12\left[cos\left( \frac{2\pi }{3} \right) +i\ sin\left( \frac{2\pi }{3} \right) \right]$