For a cartesian equation

Given r = <span>10 tan(θ) sec(θ)

Therefore,</span>the curve is a parabola opening upward with vertex (0, 0).
1,32 2,16, 4,8
That's all I got so it's 3
Sorry if I got it wrong or missed some
I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is 
Another possible answer is 
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have

In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)
Answer:
Im choosing A and yes that would be great
Step-by-step explanation: