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vivado [14]
3 years ago
9

Triangle D E F is reflected across D F to form triangle E G F. The lengths of sides E F and F G are congruent. To prove that ΔDE

F ≅ ΔDGF by SAS, what additional information is needed? ∠DEF ≅ ∠ DGF ∠DFE ≅ ∠ DFG DE ≅ DG DG ≅ GF
Mathematics
2 answers:
Serjik [45]3 years ago
7 0

Answer:

\angle DFE = \angle DFG

Step-by-step explanation:

Given

See attachment for complete question

Required

What makes DEF and DGF congruent

We have:

EF = GF --- this is indicated by the single line on both sides

Also:

DF = DF --- both triangle share same side

For SAS to be true;

2 sides and 1 angle must be equal in either triangles

So far, we have:

EF = GF ---- S

DF = DF ---- S

The additional to complete the proof is:

\angle DFE = \angle DFG ---- angle between the above sides

My name is Ann [436]3 years ago
3 0

Answer:

DE ≅ DG

Step-by-step explanation:

Edge 2021 :)

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