Question

Triangle D E F is reflected across D F to form triangle E G F. The lengths of sides E F and F G are congruent. To prove that ΔDEF ≅ ΔDGF by SAS, what additional information is needed? ∠DEF ≅ ∠ DGF ∠DFE ≅ ∠ DFG DE ≅ DG DG ≅ GF

Answer 1

Answer:

$\angle DFE = \angle DFG$

Step-by-step explanation:

Given

See attachment for complete question

Required

What makes DEF and DGF congruent

We have:

$EF = GF$ --- this is indicated by the single line on both sides

Also:

$DF = DF$ --- both triangle share same side

For SAS to be true;

2 sides and 1 angle must be equal in either triangles

So far, we have:

$EF = GF$ ---- S

$DF = DF$ ---- S

The additional to complete the proof is:

$\angle DFE = \angle DFG$ ---- angle between the above sides

Answer 2

Answer:

DE ≅ DG

Step-by-step explanation:

Edge 2021 :)