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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics

1 answer:

kiruha [24]3 years ago

6 0

Answer:

Triangular pyramid: 6

Triangular prism: 9

Rectangular pyramid: 8

Rectangular prism: 12

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What is 0+0? (i obviously know it but its to give out points.)

Reptile [31]

Answer:

Step-by-step explanation:

0+0=0

6 0

3 years ago

Help help math math math

natka813 [3]

Answer:

Yes, this is a function

Step-by-step explanation:

You know this because it passes the vertical line test.

I hope this helps!

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2 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

3x + 2 = -13. Plz help

mote1985 [20]

The answer is -5 hope this helps

3 0

3 years ago

Read 2 more answers

Katy buys 4 DVDs every 2 weeks. How many DVDs will she buy in 14 weeks?

Lena [83]

Answer:

Step-by-step explanation:

Every 2 weeks 4 DVDs are purchased, so you have to multiply 14 times two, or 7 by 4. And the answer you get either way is 28.

4 0

3 years ago