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Contact [7]
3 years ago
7

What does 9a^2 + 2b^2 if a=4 and b=7?

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0

Answer:

242

Step-by-step explanation:

zhuklara [117]3 years ago
6 0

Answer:

242

Step-by-step explanation:

Given

9a² + 2b² ← substitute a = 4 and b = 7

= 9(4)² + 2(7)²

= 9(16) + 2(49)

= 144 + 98

= 242

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I dont know. Help?<br> Please and Thanks
a_sh-v [17]

Answer:

Y' (5, -3), Z' (3, -2)

Step-by-step explanation:

The translation is right 4 and down 1.  Since you are going from (3, -4) to (7, -5), to get from 3 to 7 on the x axis you move right 4. To get from -4 to -5 on the y axis, you go down 1.

Y (1, -2) add 4 to the x value. 1 + 4 = 5.  Add -1 to the y value. -2 + -1 = -3. Y' (5, -3)

Z (-1, -1). Add 4 to the x value. 4 + (-1) = 3.  Add -1 to the y value. -1 + (-1) = -2.

4 0
3 years ago
Using the number line above, select the number that would be the opposite of Point T.
erik [133]

Answer:

-8

Step-by-step explanation:

i feel its correct

6 0
3 years ago
What is 72 % of 350 friends
Elden [556K]
'is' in mathematics means equal
<span>'of' in mathematics means multiplication

72% can also be written as 72/100

We are solving for the variable 'x'

</span>x = \frac{72}{100} \times 350\\\\x = 72 \times 3.5\\\\\boxed{\bf{x = 252}}<span>
</span>
3 0
4 years ago
Read 2 more answers
Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = ∞ e−
poizon [28]

f(t)=\begin{cases}\cos t&\text{for }0\le t

The Laplace transform is then

\mathcal L_s\{f(t)\}=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi e^{-st}\cos t\,\mathrm dt

Let I denote the integral we want to compute. Integrating by parts, setting

u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt

\mathrm dv=\cos t\,\mathrm dt\implies v=\sin t

gives

\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\int_0^\pi e^{-st}\sin t\,\mathrm dt

Integrate by parts again, setting

u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt

\mathrm dv=\sin t\,\mathrm dt\implies v=-\cos t

Then

\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\left(-e^{-st}\cos t\bigg|_{t=0}^{t=\pi}-s\int_0^\pi e^{-st}\cos t\,\mathrm dt\right)

I=e^{-st}(\sin t-s\cos t)\bigg|_{t=0}^{t=\pi}-s^2I

(s^2+1)I=s(e^{-\pi s}+1)

I=\dfrac s{s^2+1}(e^{-\pi s}+1)

7 0
4 years ago
Find the value of k for which the matrix A = [2 -5 9 -1 3 -5 7 1 k] has rank 2. k = _________.
chubhunter [2.5K]

Answer:

k = 13

Step-by-step explanation:

Matrix is;

A =

[2 -5 9]

[-1 3 -5]

[ 7 1 k ]

Number of unknowns is less than the rank of 2. Thus, the determinant has to be zero for us to find k.

Thus, we have;

2((3 × k) - (-5 × 1)) -(-5)((-1 × k) - (-5 × 7)) + 9((-1 × 1) - (7 × 3)) = 0

Simplifying further gives;

2(3k +5) + 5(-k + 35) + 9(-22) = 0

6k + 10 - 5k + 175 - 198 = 0

k - 198 + 185 = 0

k - 13 = 0

k = 13

5 0
3 years ago
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