Answer:
Below.
Step-by-step explanation:
4x^2 - 4x - 1 = 0
This will not factor.
But 4x^2 - 4x + 1 = 0 will:
= (2x - 1)(2x - 1) = 0
x = 0.5 (*2)
Answer: 
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Explanation:
Use the pythagorean trig identity 
and plug in the fact that 
Isolating sine leads to 
. I'm skipping the steps here, but let me know if you need to see them.
The result is negative because we're in quadrant 4, when y < 0 so it's when sine is negative.
Therefore,
1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)
2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)
3. Point (-4, 3) lies in Quadrant II
4. Point (6, 0) lies on the x-axis
5. Any line with no slope is parallel to the y-axis
7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1
8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)
9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6
10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True
Answer:
Answer: (7,-2)
Step-by-step explanation:
Look at the formula
1) (x – h)^2 + (y – k)^2 = r2
the center is described by (h,k)
now look at
(x – 7)^2 + (y +2)^2 = 25
here h=7
but k= -2 because is (y+2) =(y-(-2))
"The product" means you're multiplying the two numbers.
"a number" refers to a variable.
"increased" means you're adding.
2x + 7 = -36
