What is the square root of 15.6 to the nearest integer?

Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!

blagie [28]

Question 4

1) $\overline{BD}$ bisects $\angle ABC$ , $\overline{EF} \perp \overline{AB}$ , and $\overline{EG} \perp \overline{BC}$ (given)

2) $\angle FBE \cong \angle GBE$ (an angle bisector splits an angle into two congruent parts)

3) $\angle BFE$ and $\angle BGE$ are right angles (perpendicular lines form right angles)

4) $\triangle BFE$ and $\triangle BGE$ are right triangles (a triangle with a right angle is a right triangle)

5) $\overline{BE} \cong \overline{BE}$ (reflexive property)

6) $\triangle BFE \cong \triangle BGE$ (HA)

Question 5

1) $\angle AXO$ and $\angle BYO$ are right angles, $\angle A \cong \angle B$ , $O$ is the midpoint of $\overline{AB}$ (given)

2) $\triangle AXO$ and $\triangle BYO$ are right triangles (a triangle with a right angle is a right triangle)

3) $\overline{AO} \cong \overline{OB}$ (a midpoint splits a segment into two congruent parts)

4) $\triangle AXO \cong \triangle BYO$ (HA)

5) $\overline{OX} \cong \overline{OY}$ (CPCTC)

Question 6

1) $\angle B$ and $\angle D$ are right angles, $\overline{AC}$ bisects $\angle BAD$ (given)

2) $\overline{AC} \cong \overline{AC}$ (reflexive property)

3) $\angle BAC \cong \angle CAD$ (an angle bisector splits an angle into two congruent parts)

4) $\triangle BAC$ and $\triangle CAD$ are right triangles (a triangle with a right angle is a right triangle)

5) $\triangle BAC \cong \triangle DCA$ (HA)

6) $\angle BCA \cong \angle DCA$ (CPCTC)

7) $\overline{CA}$ bisects $\angle ACD$ (if a segment splits an angle into two congruent parts, it is an angle bisector)

Question 7

1) $\angle B$ and $\angle C$ are right angles, $\angle 4 \cong \angle 1$ (given)

2) $\triangle BAD$ and $\triangle CAD$ are right triangles (definition of a right triangle)

3) $\angle 1 \cong \angle 3$ (vertical angles are congruent)

4) $\angle 4 \cong \angle 3$ (transitive property of congruence)

5) $\overline{AD} \cong \overline{AD}$ (reflexive property)

6) $\therefore \triangle BAD \cong \triangle CAD$ (HA theorem)

7) $\angle BDA \cong \angle CDA$ (CPCTC)

8) $\therefore \vec{DA}$ bisects $\angle BDC$ (definition of bisector of an angle)

8 0

1 year ago

How do you find the height of a triangle (to calculate area)?

Lilit [14]

Answer:

The height of the triangle could be found by the Pythagoras theorem, where the result is, with the data of the exercise:

Height of the triangle = 10.392

And the area of the triangle is:

Area of the triangle = 31.176 units^2

Step-by-step explanation:

When you have two measurements of a triangle, as the case in the picture, you can find the third with the Pythagoras theorem, which is:

(opposite leg)^2 + (adjacent leg)^2 = hypotenuse^2

As you can see in the picture, the measurement of the hypotenuse is 12, and the opposite leg could be 6, for this reason, we're gonna clear the adjacent leg of the formula above:

(opposite leg)^2 + (adjacent leg)^2 = hypotenuse^2
(adjacent leg)^2 = hypotenuse^2 - (opposite leg)^2

Now, we can replace the values in the formula obtained:

(adjacent leg)^2 = hypotenuse^2 - (opposite leg)^2
(adjacent leg)^2 = 12^2 - 6^2
(adjacent leg)^2 = 144 - 36
(adjacent leg)^2 = 108

Now, as we just need the adjacent leg, we take the square root of both sides:

adjacent leg = $\sqrt{108}$
adjacent leg = 10.392 approximately.

Now, with these data, we can find the area of the triangle with the next formula:

Area of a triangle = (base * height) / 2
And we replace the measurements:
Area of a triangle = (6 * 10.392) / 2
Area of a triangle = 31.176

As the image does not contain units, it would be simply this number, however, you should know that the area units are usually given squared, for example: in^2 or ft^2.

4 0

2 years ago

2/3 * (-3) h SD j ni djndjifnr

Eddi Din [679]

2/3 x (-3)
-2/3 x3
= -2

5 0

2 years ago

A 4-column table with 3 rows. Column 1 has entries run, do not run, total. Column 2 is labeled lift weights with entries 40, bla

alexandr1967 [171]

Answer:

A Totals row in Access helps you see, at a quick glance, what the totals are for columns on a datasheet. For example, in a table of purchase information, we can show the sum of the price, or units purchased, or a total count of the items by adding a Totals row to the datasheet:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Hey you! I think I need your help with this one - Thanks~

timofeeve [1]

Hey Gary!

The volume of a cylinder is PiR^2h, or 3.14(r^2)h.
Let's define our measures.
Pi is 3.14 (simplified). However, our answer is requested in terms of Pi.
Our radius is 5.
Our height is 14.
Let's plug in our numbers.

5^2 • 14 • Pi
5^2 = 25
25 • 14 = 350.

350Pi is our answer.
However, rememver that we need to end our answer in units cubed, as we are using a 3-dimensional figure. Our answer is 350Pi in^3.
Your answer is B.)

I hope this helps!

5 0

2 years ago

Read 2 more answers