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Natasha2012 [34]

2 years ago

5

During second period, Evan completed a grammar worksheet. He got 27 out of 36 questions correct. What percentage did Evan get co

rrect?

2 answers:

s2008m [1.1K]2 years ago

3 0

Answer:

75%

Step-by-step explanation:

So we have to multiply by 100: $\frac{27}{36}$ × 100

Divide 27 and 36 by 9: $\frac{3}{4}$ × 100

Divide 100 by 4: 3 × 25

Evan got 75% correct

lapo4ka [179]2 years ago

3 0

Answer:

75%

Step-by-step explanation:

So, if 36 questions = 100%

1 question = 2.777777%

and he answered 27 questions correct u would multiply the amount of questions he got and the percentage a questions stands for

So,

2.7777%× 27

=75%

Evan got a percentage of 75% in the grammer work sheet

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Answer:

24, 48, 108

Step-by-step explanation:

2:9:4

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2 years ago

Cosθ=−2√3 , where π≤θ≤3π2 .

Alex787 [66]

Answer:

$sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we know that

Applying the trigonometric identity

$sin^2(\theta)+ cos^2(\theta)=1$

we have

$cos(\theta)=-\frac{\sqrt{2}}{3}$

substitute

$sin^2(\theta)+ (-\frac{\sqrt{2}}{3})^2=1$

$sin^2(\theta)+ \frac{2}{9}=1$

$sin^2(\theta)=1- \frac{2}{9}$

$sin^2(\theta)= \frac{7}{9}$

$sin(\theta)=\pm\frac{\sqrt{7}}{3}$

Remember that

π≤θ≤3π/2

so

Angle θ belong to the III Quadrant

That means ----> The sin(θ) is negative

$sin(\theta)=-\frac{\sqrt{7}}{3}$

step 2

Find the sec(β)

Applying the trigonometric identity

$tan^2(\beta)+1= sec^2(\beta)$

we have

$tan(\beta)=\frac{4}{3}$

substitute

$(\frac{4}{3})^2+1= sec^2(\beta)$

$\frac{16}{9}+1= sec^2(\beta)$

$sec^2(\beta)=\frac{25}{9}$

$sec(\beta)=\pm\frac{5}{3}$

we know

0≤β≤π/2 ----> II Quadrant

so

sec(β), sin(β) and cos(β) are positive

$sec(\beta)=\frac{5}{3}$

Remember that

$sec(\beta)=\frac{1}{cos(\beta)}$

therefore

$cos(\beta)=\frac{3}{5}$

step 3

Find the sin(β)

we know that

$tan(\beta)=\frac{sin(\beta)}{cos(\beta)}$

we have

$tan(\beta)=\frac{4}{3}$

$cos(\beta)=\frac{3}{5}$

substitute

$(4/3)=\frac{sin(\beta)}{(3/5)}$

therefore

$sin(\beta)=\frac{4}{5}$

step 4

Find sin(θ+β)

we know that

$sin(A + B) = sin A cos B + cos A sin B$

so

In this problem

$sin(\theta + \beta) = sin(\theta)cos(\beta)+ cos(\theta)sin (\beta)$

we have

$sin(\theta)=-\frac{\sqrt{7}}{3}$

$cos(\theta)=-\frac{\sqrt{2}}{3}$

$sin(\beta)=\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute the given values in the formula

$sin(\theta + \beta) = (-\frac{\sqrt{7}}{3})(\frac{3}{5})+ (-\frac{\sqrt{2}}{3})(\frac{4}{5})$

$sin(\theta + \beta) = (-3\frac{\sqrt{7}}{15})+ (-4\frac{\sqrt{2}}{15})$

$sin(\theta + \beta) = -\frac{\sqrt{7}}{5}-4\frac{\sqrt{2}}{15}$

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3 years ago

If each muffin had the same amount of sugar, how many kilograms of sugar, to the nearest thousand are in each corn muffin ( 1,00

Tresset [83]

Answer:

Sorry bro I didn't understand

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2 years ago

Solve the equation 4(x + 2)= 6x + 4

SIZIF [17.4K]

The answer is x=2

show you step-by-step

step 1:simplify both sides of the equation.

(4)(x)+(4)(2)=6x+4

4x+8=6x+4

step 2:subtract 6x from both sides.

4x+8-6x=6x+4-6x

-2x+8=4

step 3: subtract 8 from both sides

-2x+8-8=4-8

-2x=-4

step 4: divide both sides by -2

-2x/-2= -4/-2

x=2

that helps you

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2 years ago