<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
Answer:
(15m^2 + 5)
Step-by-step explanation:
(m2 - 3m + 19 ) + (2m2 + m) + (4m2 - 7) + (2m2 + m) + (4m2 - 7) + (2m2 + m)
15m2 + 0m + 5
=> <u>15m^2 + 5</u>
Let the what be x
56%* x=14
x= 14/56%
x= 25%
The amount of money Blake have in the end is 3560 + (2740 - x)
In the game Amanda had $2740 in play money and Blake had $3560 in play money.
Amanda had to give some money she possessed.
Let
what remains after Amanda gave the money = x
Therefore, Blake will have the following money at the end .
The amount she gave to Blake = (2740 - x)
Blake money = 3560 + (2740 - x)
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