Answer:
(6, 0) is located on the x-axis
Explanation:
For a point to be on the x-axis, its y-value must equal 0. (6, 0) has an x-value of 6 and a y-value of 0.
"(0, 5) is located at the origin" is not true because the origin is at (0, 0).
"(0, 5) is located on the x-axis" is not true because its y-value is 5, not 0.
"(6, 0) is located at the origin" is not true because the origin is at (0, 0).
After 3 hours, you will be on 450 mile marker.
Step-by-step explanation:
<u>step 1:</u> At start, the number in the mile marker is 100
<u>step 2:</u> After 4 hours, the number in the mile marker is 300
<u>step 3:</u> The difference of 300-100= 200. In 4 hours you crossed 200 mile markers.
<u>step 4:</u> Therefore, for 1 hour you can cross= 200/4= 50 mile markers.
For 3 hours, the number of mile markers crossed= 3*50= 150 mile markers.
<u>step 5:</u> After 3 hours, the number in the mile marker will be= 300+150= 450
Question 1: <span>
The answer is D. which it ended up being <span>
0.9979</span>
Question 2: </span>
The expression P(z > -0.87) represents the area under the standard normal curve above a given value of z. What is P(z > -0.87)? Express your answer as a decimal to the nearest ten thousandThe expression P(z > -0.87) represents the area under the standard normal curve above a given value of z. What is P(z > -0.87)? Express your answer as a decimal to the nearest ten thousandth (four decimal places). So being that rounding it off would mean your answer would be = ?
Question 3: <span>
Assume that the test scores from a college admissions test are normally distributed, with a mean of 450 and a standard deviation of 100. a. What percentage of the people taking the test score between 400 and 500?b. Suppose someone receives a score of 630. What percentage of the people taking the test score better? What percentage score worse?c. A university will not admit a student who does not score in the upper 25% of those taking the test regardless of other criteria. What score is necessary to be considered for admission? </span>
z = 600-450 /100 = .5 NORMSDIST(0.5) = .691462<span><span>
z = 400-450 /100 = -.5 NORMSDIST(-0.5) = .30854
P( -.5 < z <.5) = .691462 - .30854 = .3829 Or 38.29%
Receiving score of 630:
z = 630-450 /100 = 1.8 NORMSDIST(1.8) = .9641
96.41% score less and 3.59 % score better
upper 25%
z = NORMSINV(0.75)= .6745
.6745 *100 + 450 = 517 Would need score >517 to be considered for admissions
</span><span>
Question 4: </span>
The z-score for 45cm is found as follows:</span>
Reference to a normal distribution table, gives the cumulative probability as 0.0099.<span>
Therefore about 1% of newborn girls will be 45cm or shorter.</span>
