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3 years ago

Quadrilateral ABCD is reflected across the x-axis. What are the coordinates of quadrilateral A´B´C´D

Mathematics

1 answer:

Natalija [7]3 years ago

3 0

Answer:

Step-by-step explanation:

the answer is d because the quadrilateral is in quadrant 3 which is (-,-)

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A plant can manufacture 50 golf clubs per

Mazyrski [523]

Answer:

The correct equation is "y=30x+6147". A further explanation is given below.

Step-by-step explanation:

The given values are:

(x1, y1) = (50, 7647)

(x2, y2) = (100, 9147)

As we know,

The slope is,

⇒ $m=\frac{y2-y1}{x2-x1}$

On substituting the given values, we get

⇒ $=\frac{9147-7642}{100-50}$

⇒ $=\frac{1500}{50}$

⇒ $=30$

Now,

⇒ $(y-y1)=m(x-x1)$

On substituting the given values in the above equation, we get

⇒ $y-7647=30(x-50)$

⇒ $y-7647=30x-1500$

On adding "7647" both sides, we get

⇒ $y-7647+7647=30x-1500+7647$

⇒ $y=30x+6147$

3 0

2 years ago

Mekela earned $65.25 for 9 hours of work. This week she earned $101.50 for 14 hours. Which equation represents the relationship

cestrela7 [59]

Y = 7.25x

Where x = hours.

You can get this by dividing the amount by the amount of hours in each pair.

6 0

3 years ago

What is the circumference area?

tia_tia [17]

I believe the circumference is 52.15.

4 0

3 years ago

Find the integral <br> ∫√(9+x)/(9-x)

densk [106]

I suppose you mean

$\displaystyle \int \frac{\sqrt{9+x}}{9-x} \, dx$

Substitute y = √(9 + x). Solving for x gives x = y² - 9, so that 9 - x = 18 - y², and we have differential dx = 2y dy. Replacing everything in the integral gives

$\displaystyle \int \frac{2y^2}{18 - y^2} \, dy$

Simplify the integrand by dividing:

$\dfrac{2y^2}{18 - y^2} = -2 + \dfrac{36}{18 - y^2}$

$\implies \displaystyle \int \left(\frac{36}{18-y^2} - 2\right) \, dy$

For the first term of this new integral, we have the partial fraction expansion

$\dfrac1{18 - y^2} = \dfrac1{\sqrt{72}} \left(\dfrac1{\sqrt{18}-y} + \dfrac1{\sqrt{18}+y}\right)$

$\implies \displaystyle \frac{36}{\sqrt{72}} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy$

The rest is trivial:

$\displaystyle \sqrt{18} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy$

$= \displaystyle \sqrt{18} \left(\ln\left|\sqrt{18}+y\right| - \ln\left|\sqrt{18}-y\right|\right) - 2y + C$

$= \displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+y}{\sqrt{18}-y}\right| - 2y + C$

$= \boxed{\displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+\sqrt{9+x}}{\sqrt{18}-\sqrt{9+x}}\right| - 2\sqrt{9+x} + C}$

6 0

2 years ago

Which completely describes the polygon A. equilateral B. equiangular C. regular

hodyreva [135]

Answer:

The most complete description would be "regular."

Step-by-step explanation:

A square is a polygon with all four sides congruent and all four angles congruent. This is also the definition of a regular polygon.

6 0

3 years ago

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