Question

Bean seeds from supplier A have 85% germination rate and those from supplier B have 75% germination rate. A seed-packing company purchases 40% of its seed from A, 60% from B, and mix them together. Find the probability that a seed selected at random from the mixed will germinate.

Answer 1

Answer:

0.79 = 79% probability that a seed selected at random from the mixed will germinate.

Step-by-step explanation:

Probability of a seed germinating:

85% of 40%(from company A)

75% of 60%(from company B)

Then

$P = 0.85*0.4 + 0.75*0.6 = 0.79$

0.79 = 79% probability that a seed selected at random from the mixed will germinate.