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g100num [7]
3 years ago
15

Write the numbers from least to greatest 8.00 8.30 0.800 0.83

Mathematics
2 answers:
AfilCa [17]3 years ago
7 0

Answer:

0.800, 0.83, 8.00, 8.30

Step-by-step explanation:

vovikov84 [41]3 years ago
3 0

Answer:

0.800, 0.83, 8.00, 8.30

Step-by-step explanation:

⭐ Answered by Kakashi ʕ •㉨• ʔ⭐

⭐ Brainliest would be appreciated! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

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What values of c and d make the equation true? Assume x>0 and 20.
Grace [21]

Answer:

c=1 and c=3

Step-by-step explanation:

If x>0 and y>0, then

\sqrt{\dfrac{50x^6y^3}{9x^8}}=\sqrt{\dfrac{25\cdot 2y^2\cdot y}{9x^2}}=\dfrac{5y\sqrt{2y}}{3x}.

9x

8

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y

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If

\dfrac{5y\sqrt{2y}}{3x}

3x

5y

2y

is equal to

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then

\begin{gathered}y=y^c\Rightarrow c=1,\\ \\3x=dx\Rightarrow d=3.\end{gathered}

y=y

c

⇒c=1,

3x=dx⇒d=3.

5 0
2 years ago
28 (y - 1/7) = 28y - ?Rewrite, using the distributive property
Irina-Kira [14]

Given:

28(y-\frac{1}{7})=28y\text{ - ?}

To rewrite using distributive property, distribute the 28 to all values inside the parenthesis.

Thus, we have:

\begin{gathered} (28\ast y\text{ )-(28}\ast\frac{1}{7}) \\ =28y\text{ - 4} \end{gathered}

ANSWER:

28(y-\frac{1}{7})=28y\text{ - }4

28y - 4

4 0
2 years ago
A bag contains 3 red marbles, 4 blue marbles and 5 yellow marbles.
hjlf

Answer:

1/9

Step-by-step explanation:

i may be wrong

you add all of them together

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6 0
3 years ago
The total cost to play paintball can be represented by the expression (48x+54). If Rocco and five friends split the cost equally
KonstantinChe [14]

Answer:

8x + 9

Step-by-step explanation:

The total number of people splitting the cost equally = Rocco and five friends = 6 people

The total cost to play paintball can be represented by the expression (48x+54)

The cost for each person is calculated as: The total cost to play paintball/ Total number of people

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Therefore, the cost for each person is

8x + 9

6 0
3 years ago
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Tatiana [17]

Answer:

The 2017  year is out of proportion.

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That graph should be at about half to 3/4 the height of the average heights of the other bars.

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