Answer:
d=10u
Q(5/3,5/3,-19/3)
Step-by-step explanation:
The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane 
, then r will have the next parametric equations:
To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T
Substitute the value of 
in the parametric equations:
Those values are the coordinates of Q
Q(5/3,5/3,-19/3)
The distance from Po to the plane
The equation of the line would be
y = mx+b
where m is the slope, b is the y intercept.
<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept
and the base is y intercept divided by slope. Therefore,</span>
A = b^2/2m
At point (2,5)
5 = 2m+b
Substitute that in the area
A = b^2/5-b
to find the least area, differentiate the area with respect to the height and equate it to 0
dA/db = 0
<span>find b and
use that to find m. Then, you can have the equation of the line.</span>
Answer:
___Its the first option___
C would be the answer as
is the same thing as x * x * x * x.
Answer:
B
Step-by-step explanation:
Ethical concerns!
Good luck on your assignment hope this helps!:)
