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BigorU [14]
3 years ago
13

Please help me, I dont know this :double s, then subtract t from the result

Mathematics
2 answers:
lesantik [10]3 years ago
8 0
Basically just convert this into an equation:
Let’s use “x” as the result
“•” is the multiplication symbol

Double s: s•2
Subtract t from result: =x-2

So, s•2=x-2
frez [133]3 years ago
5 0
Double s is usually written 2s
Then just subtract t
The answer will be 2s - t
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The elevation of Mount Everest is 29028 feet . The elevation of the dead sea is - 485 feet. What is th difference in the elevati
LUCKY_DIMON [66]
Difference = subtract
29028-(-485) if you subtract a negative the sign changes to positive and the subtraction changes to addition so ur answer is 29513
4 0
4 years ago
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Teresa has scored 77, 80, 63, 61 and 92 on previous test what score does she need on her next test on her average will be 77
Rainbow [258]
Average = 77=(77+80+63+61+92+Next test)/6

Therefore, 77*6=77+80+63+61+92+Next test

Next test score = (77*6)- (77+80+63+61+92)= 89
6 0
3 years ago
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Ruby is visiting San Francisco. From her hotel she walks 4 blocks east and 2 blocks north to a coffee shop. Then she walks 5 blo
NeTakaya
I'm not sure if you have done vectors as of yet, but you would first add the x components and y components separately. 

x-components: 4 blocks + 5 block = 9 blocks 
y-component: 2 blocks + 1 block = 3 blocks

Magnitude of this: √(x₂-x₁)²+(y₂-y₁)² 
= √(9)²+(3)²
=√81+9 
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Angle of of the resultant vector; 

tanθ=y/x 
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3 0
3 years ago
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HELP ME OUT PLEASE!!!!!
g100num [7]

Answer:

(4,3)

Step-by-step explanation:

6 0
2 years ago
18. Find the center, vertices, and foci of the ellipse with equation x squared divided by 225 plus y squared divided by 625 = 1.
KengaRu [80]

Answer:

Center (0,0)

Vertices (-15,0), (15,0), (0,-25), (0,25)

Foce (0,-20), (0,20)

Step-by-step explanation:

You are given the ellipse equation

\dfrac{x^2}{225}+\dfrac{y^2}{625}=1

The canonical equation of ellipse with center at (0,0) is

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1

So,

a^2=225\Rightarrow a=15\\ \\b^2=625\Rightarrow b=25

Hence, the center of your ellipse is at (0,0) and the vertices are at points (-15,0), (15,0), (0,-25) and (0,25)

This ellipse is strengthen in y-axis, so

c=\sqrt{b^2-a^2}=\sqrt{625-225}=\sqrt{400}=20

and the foci are at points (0,-20) and (0,20).

6 0
3 years ago
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