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3 years ago

>The value of the expression 6x when x = 2 is

Mathematics

2 answers:

yulyashka [42]3 years ago

8 0

Answer:

Step-by-step explanation:

6x means 6 times x so when you replace x with 2 you get 6×2= 12

Natali [406]3 years ago

4 0

Answer:

Step-by-step explanation:

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(z^2-11z+30)/(z-5)

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4 years ago

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The first is 150/3=50. The second is 800/2.5 =320. Number 10 is about .44 and number 12 is .60

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Step-by-step explanation:

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3 years ago

Nine fourths minus two thirds

Yuki888 [10]

Answer:

$1 \frac{7}{12} \: or \: 1.583$

Step-by-step explanation:

nine fourths is also

$\frac{9}{4}$

two thirds is also

$\frac{2}{3}$

subtract,

$\frac{9}{4} - \frac{2}{3}$

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3 years ago

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

<u>Part a)</u> How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

<u>Part b</u>) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

4 years ago

>The value of the expression 6x when x = 2 is​

>The value of the expression 6x when x = 2 is