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4vir4ik [10]
3 years ago
9

Help with math I have to have 20 characters or more to ask question...

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

x=-\frac{113}{3}

Step-by-step explanation:

First, we need to solve the angle inside the triangle. That would be 55+40+angle measure=180

angle measure=85°

Now that we know that, we can solve for x by setting 85-3x-18 equal to 180° because these two values form a linear pair which is 180°.

Let's use some simple algebra to solve for x:

85-3x-18=180

67-3x=180

-3x=113

x=-\frac{113}{3} or about -37.67

Hope this helps!! :)

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The number of trucks registered in a city increases by 10% each year. Initially, there were 100 trucks registered. There were 11
Alex787 [66]

Answer:

214 trucks

Step-by-step explanation:

Un= amount after a certain time period

Uo= initial amount

n= number of time periods

i= interest rate

Equation used : Un= Uo (1+i)^n

Un=100(1.1)^8 = 214.36 , but you can't have half a truck so round and the answer would simply be 214.

5 0
4 years ago
Simplfy the expression 10(m-3n)
ddd [48]

Answer:

10m-30n

Step-by-step explanation:

distribute

4 0
3 years ago
Identify the initial amount a and the growth factor b in the exponential function.
alina1380 [7]

Given the equation A (x) = 30 x 8.3 ^x, we can get the initial amount of A when x is equal to zero. Therefore:

A (0) = 30 * 8.3^0

A (0) = 30

In this case the equation grows by 8.3 times as x increases. Therefore the growth factor is 8.3.

Answers:

initial amount = 30

growth factor = 8.3

The answers are not in the given choices. I believe you are giving the wrong equation. If the correct equation here is:

A (x) = 680 x 4.3 ^x 

Then the answers are:

initial amount = 680

growth factor = 4.3

The answers are now in the choices given.

7 0
3 years ago
what are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x- pi) from x = 0 to x= 2 pi?
julsineya [31]

Answer:

\frac{\pi }{2} and \frac{3\pi }{2}

Step-by-step explanation:

To find the max points we need to take the derivative of the function and then find the critical values.

First we take the derivative:

f(x) = 4cos(2x-\pi )\\f'(x)=-4sin(2x-\pi )(2)\\f'(x)=-8sin(2x-\pi )\\

Now we need to find when f'(x)=0 to find the critical values.

0=-8sin(2x-\pi )\\0=sin(2x-\pi )\\sin^{-1}0=2x-\pi \\0=2x-\pi \\\pi =2x\\\frac{\pi }{2} =x

The critical values will be

\frac{\pi }{2} n for any integer n

between 0 and 2 pi, the critical values will be

0, \frac{\pi }{2} ,\pi ,\frac{3\pi }{2},2\pi

We can determine if these are minimums or maximums by using the second derivative test.

So we need to take the second derivative;

f'(x)=-8sin(2x-\pi )\\f''(x) = -8cos(2x-\pi )(2)\\f''(x)=-16cos(2x-\pi)

We need to see if the second derivative is positive or negative to determine if it is a max or min.

f''(0) = 16\\f''(\frac{\pi}{2})=-16\\f''(\pi )=16\\f''(\frac{2\pi}{3}) = -16\\

Since the second derivative is negative at

\frac{\pi }{2} and \frac{3\pi }{2}

we know both of those are the x-values of maximums.

5 0
4 years ago
Find the slope of the line through the points (3,7) and (5,19)
Sedbober [7]

Answer:

<u>1</u><u>2</u>

2

Step-by-step explanation:

(3,7)(5,19)

(x,y)(x,y)

<u>y2</u><u>(</u><u>1</u><u>9</u><u>)</u><u>-</u><u> </u><u>y1</u><u>(</u><u>7</u><u>)</u>

x2(5)-x1 (3)

formula. <u>y2-y1</u>

x2-x1

7 0
3 years ago
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