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Papessa [141]
2 years ago
5

6. Which number is equal to 7(3.5x104) written in scientific notation?

Mathematics
1 answer:
vivado [14]2 years ago
4 0

Answer:

C

Step-by-step explanation:

This is basically:

7 x 3.5 x 104 = 24.5 x 104

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An irrational number between -2 and -1<br><br> a rational number between -2 and -1
leva [86]

Answer:

An irrational number between -2 and -1 would be \frac{-\pi }{2}

A rational number between -2 and -1 would be -1.5

Step-by-step explanation:

\frac{-\pi }{2} = -1.570796... This number does not have repeating decimals, patterns, and it isn't a terminating decimal. It is irrational.

-1.5 is a terminating decimal, therefore it is rational, as well as between -2 and -1.

6 0
1 year ago
Calculate the slope of the line that goes<br> through the ordered pairs (0, -7), and (-2,-27).
Aleks04 [339]

Answer:

10

Step-by-step explanation:

To find the slope subtract the points like the following:

(-27-(-7)/(-2-0)

= -20/-2

=10

So, the slope is 10.

3 0
2 years ago
Input value for the function machine that gives an output value of 3.
krek1111 [17]

Answer:

x = –1

Step-by-step explanation:

From the question given above, the following data were obtained:

y = √(–2x + 7)

y = 3

x =?

The value of x can be obtained as follow:

y = √(–2x + 7)

3 = √(–2x + 7)

Take the square of both side

3² = –2x + 7

9 = –2x + 7

Collect like terms

9 – 7 = –2x

2 = –2x

Divide both side by –2

x = 2 / –2

x = –1

3 0
2 years ago
A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0
3 years ago
tom is making a rectangular garden. he decides to make the garden 30 ft long by 15 ft wide. Later, tom decides to keep the lengt
UkoKoshka [18]
Width=25 got me m; iyyyyg
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