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Sunny_sXe [5.5K]
3 years ago
6

What is the area of the circle in square units? Select ALL that apply.

Mathematics
1 answer:
lukranit [14]3 years ago
7 0
The answer is F.)
Approximately 50
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John drove from house to work at an average speed of 30 mph, trip took 40 minutes. How far in meters is his house to work?
AysviL [449]

Answer:

20 meters

Step-by-step explanation:

Firstly we need to know that distance = speed * time

In this particular question, we have the time and the speed, we are only told to find the distance.

Now as we can see, the units are not consistent. While the average speed is 30mph, the time is not in hours but minutes. So practically, we have to convert the time to hours.

Since there are 60 minutes in an hour, the number of hours in 40 minutes would be 40/60 = 2/3 hours.

Now we can proceed to find the distance. We simply multiply the average speed with the time.

Hence, that is 30 * 2/3 = 20 meters

5 0
3 years ago
Describe the relationship between two variables when the correlation coefficient r is one of the following. (a) near –1 strong
zepelin [54]

Answer:

a) strong negative linear correlation.

b) Weak or no linear correlation.

c) strong positive linear correlation.

Step-by-step explanation:

The correlation coefficient r measures the strength and direction (positive or negative) of two variables. The correlation coefficient r is always between -1 and 1. When the coefficient r is negative then the direction of the correlation is downhill (negative) and when it's positive then it's an uphill correlation (positive). Similarly, as the coefficient is closer to -1 or 1 the correlation is stronger, with zero being a non linear relationship.

Now back to the question:

a) Near -1: as we said before, this means an strong negative (-1) linear correlation.

b) Near 0: weak or no linear correlation (we cannot say if its positive or negative because we don't know it it's near zero from the right (positive numbers) or the left (negative numbers)

c) Near 1: strong positive (close to +1) linear correlation

3 0
3 years ago
If u can, pls help me ( I WANTED TO PUT 30 POINTS, BUT I ACCIDENTALLY CLICKED 10
RoseWind [281]
I really can't see what you wrote
3 0
3 years ago
ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?
MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = \sqrt{(x_2-x_1)^2 +( y_2-y_1)^2

Step 1: Finding the length of  EF

By using distance formula,

EF = \sqrt{(-7 - 0)^2 + (4-0)^2}

EF = \sqrt{(49) + (16)}

EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\

Step 2: Finding the length of  FG

By using distance formula,

FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}

Step 2: Finding the length of  GE

GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8

Thus we could see that the sides EF = FG

So it is  a isosceles triangle.

6 0
3 years ago
1/8 + 2(1/2m + 5) = 1/4m + 7
Neporo4naja [7]
<span>1/8 + 2(1/2m + 5) = 1/4m + 7 would equal m=-25/6</span>
7 0
3 years ago
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