$\bf g(x)=\cfrac{1}{x^2}~\hspace{5em}\cfrac{g(x+h)-g(x)}{h}\implies \cfrac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h} \\\\\\ \textit{using the LCD of }(x+h)^2(x^2)\qquad \cfrac{\frac{x^2-(x+h)^2}{(x+h)^2(x^2)}}{h}\implies \cfrac{x^2-(x+h)^2}{h(x+h)^2(x^2)} \\\\\\ \cfrac{x^2-(x^2+2xh+h^2)}{h(x+h)^2(x^2)}\implies \cfrac{\underline{x^2-x^2}-2xh-h^2}{h(x+h)^2(x^2)}\implies \cfrac{-2xh-h^2}{h(x+h)^2(x^2)}$

$\bf \cfrac{\underline{h}(-2x-h)}{\underline{h}(x+h)^2(x^2)}\implies \cfrac{-2x-h}{(x+h)^2(x^2)}\implies \cfrac{-2x-h}{(x^2+2xh+h^2)(x^2)} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{-2x-h}{x^4+2x^3h+x^2h^2}~\hfill$

4 0

3 years ago

NEED HELP ASAP WILL GIVE BRAINLESTSame scenario - different question. You may use your notes on this checkpoint.

bixtya [17]

Answer:

Step-by-step explanation:

There is no meaningful difference between the two mean monthly temperatures. Since the two MADs are 15 degrees and 13.7 degrees, there is no meaningful difference.

6 0

2 years ago

A trapezoid has four sides with two sides that are the same length. Let the two sides have length x. The longest side has a leng

Oduvanchick [21]

Answer:

fx21

Step-by-step explanation:

5 0

2 years ago

A number x is more than –6 and at most 8.

konstantin123 [22]

X=-4 that might be the correct awnser

6 0

3 years ago