Answer:
a)

Z = -1.58 means that a reading speed of 340 wpm is 1.58 standard deviations below the mean reading speed.
b)

Z = 0.67 means that a reading speed of 475 wpm is 0.67 standard deviations above the mean reading speed.
c)

Z = -0.25 means that a reading speed of 420 wpm is 0.25 standard deviations below the mean reading speed.
d)

Z = 2.92 means that a reading speed of 610 wpm is 2.92 standard deviations above the mean reading speed.
Step-by-step explanation:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The z-score measures how many standard deviations a measure X is above or below the mean.
In this problem, we have that:

a. 340 wpm



Z = -1.58 means that a reading speed of 340 wpm is 1.58 standard deviations below the mean reading speed.
b. 475 wpm



Z = 0.67 means that a reading speed of 475 wpm is 0.67 standard deviations above the mean reading speed.
c. 420wpm



Z = -0.25 means that a reading speed of 420 wpm is 0.25 standard deviations below the mean reading speed.
d. 610wpm



Z = 2.92 means that a reading speed of 610 wpm is 2.92 standard deviations above the mean reading speed.
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Answer:
-y = 3x - 4
Step-by-step explanation:
- - 3x to get - y + 2 = - 3x
- - 2 to get - y = - 3x - 2
- Replace the - 2 with 4 from the points
- Make it a negative
Answer:
A.f(x)=ln(−x)
Step-by-step explanation:
<u>Graph Of The Logarithm Function</u>
The domain of the logarithm function, written as y=log(u), is u>0. This means that it doesn't exist for any value of u less than or equal to zero
We can see in the graph the function is defined for all negative values of x. It means that if we choose any of the points in the graphs, the selected function must exist at that point.
Let's pick the point (-7,2). If we set x=-7 in the second option B, it would produce log(-5) which is not defined. A similar thing happens when using the third function to produce ln(-8) who doesn't exist either. The function D is not good because it would take log(-7). The only possible function is the first one f(x)=ln(-x), when evaluating f(-7)=ln7=1.95
This is a polynomial of degree 4, because you have 4 roots real or imaginary:1st) x= 5 →(x-5)=0
2nd) x = - 3→(x+3) =0
3rd) x = -1+3i →(x+1-3i) = 0
and the 4th one that is not mentioned which is the conjugate of
-1+3i, that is -1-3i (in any polynomial if a root has the form of a+bi, there is always a conjugate root = a-bi)
4th) x= -1-3i→(x+1+3i) = 0
Hence the polynomial =(x-5)(x+3)((x+1-3i)(x+1+3i)
Solving the above will give you (unless I am mistaken, pls recalculate):
x⁴-9x²-50x-150<u />