Step-by-step explanation:
follow the above attachment, hope this helps you.
Answer:
![x = 4](https://tex.z-dn.net/?f=x%20%3D%204)
![y =1](https://tex.z-dn.net/?f=y%20%20%3D1)
Step-by-step explanation:
Given
The attached figure
Required
x and y
If the attached is a parallelogram, then:
<em>Either segment of a diagonal are equal; So, we have:</em>
![3x = 12](https://tex.z-dn.net/?f=3x%20%3D%2012)
![x + y = 5y](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%205y)
<em></em>
In ![3x = 12](https://tex.z-dn.net/?f=3x%20%3D%2012)
Divide both sides by 3
![x = \frac{12}{3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B12%7D%7B3%7D)
![x = 4](https://tex.z-dn.net/?f=x%20%3D%204)
Substitute
in ![x + y = 5y](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%205y)
![4 + y = 5y](https://tex.z-dn.net/?f=4%20%2B%20y%20%3D%205y)
Collect like terms
![5y - y =4](https://tex.z-dn.net/?f=5y%20-%20y%20%3D4)
![4y = 4](https://tex.z-dn.net/?f=4y%20%3D%204)
Divide both sides by 4
![y = \frac{4}{4}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B4%7D%7B4%7D)
![y =1](https://tex.z-dn.net/?f=y%20%20%3D1)
so what is the question that u are asking. I'll help you out
Assuming that these are 6-sided dice, We can roll a 6 and a 3, and 5 and a 2, or a 4 and a 1, in order to get a difference of 3.
1/6 chance for each side, 1/36 to roll any one of those combinations.
Multiply that chance by 3, for the 3 combinations we can roll to give us a difference of 3, and we get 3/36, or an 8.(3)% reoccurring chance.<span />