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3 years ago

I need help please.........................

Mathematics

2 answers:

Nastasia [14]3 years ago

5 0

......?Did You Find It..?

motikmotik3 years ago

3 0

Answer:

11.25

Step-by-step explanation:

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Jamal can run 1 mile in 5.05 minutes. If Jamal maintains this pace during a 5- kilometer race, he expects to brake the course re

erik [133]

Let’s make an equation 5x=15.25. We should get x by itself by dividing both sides by 5. Which should leave x=3.5, which would mean he’d have to run faster, so no. It’s not reasonable

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3 years ago

Engine now what the area and perimeter is for this triangle

VLD [36.1K]

Area formula A=hbb/2
Perimeter formala is a+b+c

6 0

3 years ago

The mean weight of the seven linebackers was 236 pounds. The first six linebackers weighed 215lb, 305lb, 265lb, 196lb, 221lb, an

Nadya [2.5K]

Answer:

The weight of the seventh linebacker is = 214 lb.

Step-by-step explanation:

Given:

Mean of 7 linebackers = 236 lb

The weights of first 6 linebackers are:

215 lb, 305 lb, 265 lb, 196 lb, 221 lb and 236 lb

To find the weight of seventh linebacker.

Solution:

Let the weight of the seventh linebacker be = $x$

The mean of 7 line backers will be given as:

⇒ $\frac{215+305+265+196+221+236+x}{7}$

The mean of the 7 linebackers is given = 236 lb

Thus, the equation to find $x$ will be :

$\frac{215+305+265+196+221+236+x}{7}=236$

Simplifying.

$\frac{1438+x}{7}=236$

Multiplying both sides by 7.

$7.\frac{1438+x}{7}=236(7)$

$1438+x=1652$

Subtracting both sides by 1438.

$1438-1438+x=1652-1438$

∴ $x=214$

Thus, the weight of the seventh linebacker is = 214 lb.

7 0

3 years ago

I need this soon, please.

leonid [27]

Answer:

5 10

12 5

Step-by-step explanation:

you add numbers in the same position.

2+3. 4+6

7+5. 5+2

5 0

3 years ago

Please need help thank

storchak [24]

Answer:

35 balloons

Step-by-step explanation:

If wrong srry...hope this helps

4 0

3 years ago

Read 2 more answers