Answer:
you need 100ml of 5X TAE and 400ml of water.
Step-by-step explanation:
You need to use a rule of three:
![C_1V_1=C_2V_2](https://tex.z-dn.net/?f=C_1V_1%3DC_2V_2)
where:
![\left \{ {{C_1= 5X} \atop {C_2=1X}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7BC_1%3D%205X%7D%20%5Catop%20%7BC_2%3D1X%7D%7D%20%5Cright.)
and
![\left \{ {{V_1 = V_{TAE}} \atop {V_2=500ml}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7BV_1%20%3D%20V_%7BTAE%7D%7D%20%5Catop%20%7BV_2%3D500ml%7D%7D%20%5Cright.)
Therefore:
![V_{TAE} = \frac{V_2*C_2}{C_1}](https://tex.z-dn.net/?f=V_%7BTAE%7D%20%3D%20%5Cfrac%7BV_2%2AC_2%7D%7BC_1%7D)
![V_{TAE} = 100ml](https://tex.z-dn.net/?f=V_%7BTAE%7D%20%3D%20100ml)
Then just rest the TAE volume to the final Volume and you get the amount of water that you need to reduce the concentration.
Answer: Mark up percent = 20%
Step-by-step explanation:
Given: Cost price of each T-shirt = $5.00
Amount required = $450
Total students = 75
Market price for each T-shirt to raise the required amount = (Amount required ) ÷ 75
= $450 ÷ 75
= $ 6
Mark up percent = ![\dfrac{\text{Market price - Cost price}}{\text{Cost price}}\times100](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BMarket%20price%20-%20Cost%20price%7D%7D%7B%5Ctext%7BCost%20price%7D%7D%5Ctimes100)
![=\dfrac{6-5}{5}\times100\\\\=20\%](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B6-5%7D%7B5%7D%5Ctimes100%5C%5C%5C%5C%3D20%5C%25)
Hence, Mark up percent = 20%
The answer is B, it cant be C or D because its not touching 0 and its not negative
Answer:
After 10 years the cost will be $ 97.52.
Step-by-step explanation:
This problem requires us to calculate the cost of graphing after 10 years if inflation rate is two percent. This can easily be calculated by compounding present value of current cost at the rate of 2%. Detail calculation is given below.
FV= 80 (1+2%)^10
FV = $ 97.52