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SCORPION-xisa [38]
3 years ago
8

Write 6 3/10 as a improper fractionASAPPPPP

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0

Answer:

63/10

Step-by-step explanation:

6 3/10

see, from the denominator that means 10,

multiply to whole, then 10×6,

we got 60 right;

now add numerator 60+3 = 63

here we got improper fraction,

that is 63/10

loris [4]3 years ago
5 0

Answer:

63/10

Step-by-step explanation:

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Questions 16-17 | Math 1 - 0 points Solve the graph Help needed !!
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Answer:

16) The area of the circle is 25.1 units²

17) JKLM is a parallelogram but not a rectangle

Step-by-step explanation:

16) Lets talk about the area of the circle

- To find the area of the circle you must find the length of the radius

- In the problem you have the center of the circle and a point on

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* Lets solve the problem

∵ The center of the circle is (1 , 3)

∵ The point on the circle is (3 , 5)

- Using the rule of the distance between two points

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- The distance between the two points (x1 , y1) and (x2 , y2) is:

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∴ r = √[(3 - 1)² + (5 - 3)²] = √[4 + 4] = √8 = 2√2 units

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* The area of the circle is 25.1 units²

17) To prove a quadrilateral is a parallelogram, prove that every

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* The parallelogram can be rectangle if two adjacent sides are

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- The parallel lines have equal slopes, then to prove the

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* Lets find from the graph the vertices of the quadrilateral

∵ J = (0 ,2) , K (2 , 5) , L (5 , 0) , M (3 , -3)

- The opposite sides are JK , ML and JM , KL

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∵ The slop of JK = (5 - 2)/(2 - 0) = 3/2 ⇒ (1)

∵ The slope of LM = (-3 - 0)/(3 - 5)= -3/-2 = 3/2 ⇒ (2)

- From (1) and (2)

∴ JK // LM

∵ The slope of KL = (0 - 5)/(5 - 2) = -5/3 ⇒ (3)

∵ The slope of JM = (-3 - 2)/(3 - 0)= -5/3 ⇒ (4)

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∵ The slope of JK = 3/2 and the slope of KL = -5/3

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