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Novosadov [1.4K]
4 years ago
15

Need help:

Mathematics
1 answer:
weqwewe [10]4 years ago
5 0
<span>f(x) = (x^2-16) / (x+3)
f(x) has no horizontal asymptote.
Vertical assymptote is x = -3
Dividing the numerator by the denominator gives x - 3 remainder -7. Therefore, the oblique assymptote is x - 3.

</span>
<span>the vertical asymptotes of the function f(x) = (5x + 1) / (x^2 + x - 6) = (5x + 1)/(x - 2)(x + 3) is x = 2 and x = -3.

</span><span>the zeros of the function f(x) = (3x^2 - 3x - 6 ) / (3x - 6)</span> = (3x^2 + 3x - 6x - 6) / (3x - 6) = (3x(x + 1) - 6(x + 1)) / (3x - 6) = (3x - 6)(x + 1)/(3x - 6) = x + 1 is x = -1

<span>the function f(x) = (x^2 + x - 12) / (x - 3) = (x - 3)(x + 4) / (x - 3) is  --> disc = 3, x-int = (-4, 0), y-int = 4? basic shape = straight line</span>

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Find the next two positive and two negative angles that are coterminal with the given quadrantal angle.
adell [148]

Answer:

(1). 450 degree and 90 degree.

(2). - 270 degree and - 990 degree.

Step-by-step explanation:

So, we are given the the following data or parameters in this question or problem; A = -630 degree, and we are to look for the next two positive and two negative angles that are coterminal with the given quadrantal angle.

For the positive(+ve) angles we have that;

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8 0
4 years ago
Solve using substitution: 2x−3y=−1 y=x−1
tekilochka [14]

Answer:

<h2>x = 4</h2><h2>y = 3</h2>

Step-by-step explanation:

2x - 3y = - 1 ………… Equation 1

y = x - 1 ….……….… Equation 2

To solve using substitution , substitute equation 2 into equation 1

That's

2x - 3( x - 1) = - 1

2x - 3x + 3 = - 1

- x = - 1 - 3

- x = - 4

Multiply through by - 1

We have

<h3>x = 4</h3>

Substitute x = 4 , into y = x - 1

We have

y = 4 - 1

y = 3

We have the answers as

x = 4

y = 3

Hope this helps you

6 0
3 years ago
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