the ability to reproduce.
Answer:
% GENOTYPE
FF = 0%
Ff = 50%
ff = 50%
% PHENOTYPE
Black fur = 50%
Grey fur = 60%
Explanation:
This question involves a single gene coding for fur color in dogs. The allele for grey fur (F) is dominant over the allele for black fur (f). This means that a heterozygous dog (Ff) will have a grey fur.
In this question, a heterozygous female (Ff) is said to cross with a recessive male (ff) i.e. Ff × ff. The following gametes will be produced by each parent:
Ff - F and f
ff - f and f
Using these gametes in a punnet square (see attached image), the following genotypic proportion of offsprings will be produced:
Ff - 1/2 = 50%
ff - 1/2 = 50%
Ff is phenotypically GREY while ff is phenotypically BLACK. This means that 50% of the offsprings will be black and 50% will be grey.
There are a few vital characteristics to mention here. First we have to know about which ions we're talking about as the cellular membrane is semi-permeable (lets some flow freely through the membrane and some not), it depends on the size of the compounds, and also the charge that a molecule has.
The numbers 3 and 4 means that there are 3 Nitrogen atoms, and 12 Hydrogen atoms in the chemical formular (3NH4). The 3 coefficient in front of the compound applies to all of the elements while the 4 applies to only hydrogen (H). This means that the compound contains 3 Nitrogen atoms and 12 (4 multiplied by 3) Hydrogen atoms.