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ycow [4]
3 years ago
7

Is y = 8x ² a function

Mathematics
2 answers:
leva [86]3 years ago
8 0

Answer: i dont think so but dont trust me I know nothing

Step-by-step explanation:

Lina20 [59]3 years ago
6 0

Answer:

hjb vgyguhjbhvgyugikjb n vbjnm ,gvybk n

Step-by-step explanation:

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A sports tournament has 6 teams. Each team has the same number of players. There are 60 players total. How many players does eac
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10

Step-by-step explanation:

because

60:6=10

every team has the same number of players

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3 years ago
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Numbers and expressions written in scientific notation are often used to represent measurement in a real-life situations. For ea
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2. My bedroom is (value) sq ft
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3 years ago
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What is the area of the reduced rug, in square feet?
Alinara [238K]

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100

Step-by-step explanation:

6 0
3 years ago
Ali’s earnings vary directly with the number of hours he works. Suppose that he worked 10 hours yesterday and earned $130. how m
gregori [183]

Answer: He earns $169 after 13 hours

Step-by-step explanation:

To solve this we need to find out how much he earns per hour.

This can be identified using simply division.

130/10=13

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Now we multiply 13*13=169

He earns $169 after 13 hours

4 0
4 years ago
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A rubber ball dropped on a hard surface takes a sequence of bounces, each one 1/6 as high as the preceding one. If this ball is
Brums [2.3K]

Answer:

\frac{259}{54}\text{ or }4.8\text{feet}

Step-by-step explanation:

GIVEN: A rubber ball dropped on a hard surface takes a sequence of bounces, each one \frac{1}{6} as high as the preceding one.

TO FIND: If this ball is dropped from a height of 12 feet, how far will it have traveled when it hits the surface the fifth time.

SOLUTION:

once the ball is dropped on hard surface it bounces \frac{1}{6} of preceding one and comes down the same distance.

When the ball is dropped from 12 feet height

after first hit =12\times\frac{1}{6}\text{ up}+12\times\frac{1}{6}\text{ down}=4

new height =12\times\frac{1}{6}=2\text{feet}

after second hit =2\times\frac{1}{6}\text{ up}+2\times\frac{1}{6}\text{ down}=\frac{2}{3}

new height =2\times\frac{1}{6}=\frac{1}{3}\text{ feet}

after third hit  =\frac{1}{3}\times\frac{1}{6}\text{ up}+\frac{1}{3}\times\frac{1}{6}\text{ down}=\frac{1}{9}

new height =\frac{1}{3}\times\frac{1}{6}=\frac{1}{18}\text{ feet}

after fourth hit =\frac{1}{18}\times\frac{1}{6}\text{ up}+\frac{1}{18}\times\frac{1}{6}\text{ down}=\frac{1}{54}

adding all distance =4+\frac{2}{3}+\frac{1}{9}+\frac{1}{54}

                                 =\frac{259}{54} feet

Hence the ball will travel   \frac{259}{54} feet before it hits the surface fifth time.

                                 

4 0
4 years ago
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