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Montano1993 [528]
3 years ago
13

How to factorize the following expression?pqr + pr + q + 1​

Mathematics
1 answer:
Sveta_85 [38]3 years ago
5 0
<h3>Answer:  (pr + 1)(q + 1)</h3>

===============================================

Work Shown:

Use the factor by grouping method to get the following.

pqr + pr + q + 1​

(pqr + pr) + (q + 1​)

pr(q + 1) + 1(q + 1)

(pr + 1)(q + 1)

We can use the FOIL rule, distribution, or the box method to expand out  (pr+1)(q+1) to get the original expression again. This helps confirm the answer.

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I forgot how to this can someone help please
Jet001 [13]

Answer:

1728

Step-by-step explanation:

You could write it like this

5.4 * 10^5 * 3.2 * 10^-3  

You could do this by multiplying the numbers first

5.4 * 3.2 = 17.28

Now work with the powers of 10

10^5 * 10^-3 = 10^(5 - 3) = 10^2

10^2 = 100

So the answer is 17.28 * 100 = 1728

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3 years ago
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netineya [11]
We have n/5 = 18
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6 0
3 years ago
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What is the solution for 2y – 5 – 8 + y &gt; 5?
andreev551 [17]

Answer:

y>6

Step-by-step explanation:

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Help please, i dont understand
yan [13]

Answer:

formula: y-y1 = m(x-x1)

Step-by-step explanation:

General:

1. find 2 points directly on the line and apply the formula y2-y1 over x2-x1 this answer equals m

2. then add it into the formula y-y1 = m(x-x1) remember x and y are variables so only put numbers in y1 and x1

3. solve the problem

Example:

line 1:

1. y2-y1 over x2-x1 is 4-6 over 6-4 = -1

2.  y-6 = -1(x-(-4) or y-6 = -1(x+4)

3. y-6 = -1x-4

4. y = -1x-2

3. the gradient equals: y = -1x-2

Hope this helps :) Let me know if you need a better example

5 0
3 years ago
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