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2 years ago

Find the Number of possible outcomes You flip a coin once

Mathematics

1 answer:

Ratling [72]2 years ago

4 0

Answer:

1/6*1/2= 1/12

Answer is 1/12

Step-by-step explanation:

hope this helps (:

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Flve tickets to a carnlval cost $45. How much would seven<br> tickets cost?

Alecsey [184]

Answer:

$63

Step-by-step explanation:

In order to solve this problem, we need to find the unit price, which is the price per 1 ticket in this case. To find this, we need to divide $45 by 5 because each ticket is the same amount: $45 / 5 = $9. So each ticket is $9.

Now, we need to find how much 7 tickets would cost. To do this, multiply the $9 / ticket by 7 tickets: $9 * 7 = $63.

This, 7 tickets would cost $63.

Hope this helps! God Bless u!!!

5 0

2 years ago

Read 2 more answers

Show if the following expressions are equivalent

kvasek [131]

Anwser is B i took the test

8 0

2 years ago

If you can answer 5 questions in an hour, how many questions can you complete in 3 hours? HINT: Use the proportion 5 questions :

Stella [2.4K]

Answer:

Step-by-step explanation:

1 hr: 5

2 hr: 10

3 hr: 15

3 0

3 years ago

The 2 triangles shown in the figure are similar. Find the distance "d" across the Red River

Aliun [14]

2 km... Since 1.8 is 2(.9), you do the same for the base of the smaller triangle (just multiply by two)

6 0

3 years ago

A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib

fenix001 [56]

Answer: 0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = $\mu=50\times190=9500\text{ pounds}$

Standard deviation of 50 people $=\sigma=40\sqrt{50}=40(7.07106781187)=282.84$

Then , the probability its maximum safe load will be exceeded =

$P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855$

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0

3 years ago