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abruzzese [7]
3 years ago
5

2,12,52,33,8,14

Mathematics
2 answers:
pogonyaev3 years ago
8 0
13 is the answer. You would first list the numbers from least to greatest. Then you would find which number is in the middle. But since it would be between 12 and 14, since there is no even middle, you would find the middle of 12 and 14. And 13 is between 12 and 14. Sooooooo....

<span>13 is the answer</span>
Assoli18 [71]3 years ago
3 0

Answer:

25

Step-by-step explanation:

2, 8, 12, 14, 33, 52

Median: 13

Lower quartile: 8

Upper quartile: 33

Interquartile range: 33 - 8 = 25

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Write the standard form of the line that contains a slope of 2/3 and passes through the point (1,1). Include your work in your f
Simora [160]

Answer:

2x - 3y = -1

Step-by-step explanation:

Standard form: Ax + By = C

Given: slope = 2/3 and  passes through the point (1,1)

Point slope form: y - y1 = m(x - x1)

Plug in

y - 1 = 2/3(x - 1)

Multiply both sides by 3

3(y - 1) = 2(x -1)

Distributive property

3y - 3 = 2x - 2

Since standard form: Ax + By = C so you can re-write the equation:

2x - 2 = 3y - 3

Subtract 3y from both sides

2x - 3y = -3

Add 2 to both sides

2x - 3y = -1

Answer in standard form: 2x - 3y = -1

8 0
3 years ago
The price of mailing a small package is 0.32 $ for the 1st ounce and $0.21 for each additional ounce. Sandra put $1.16 to mail h
ELEN [110]
So you would subtract 0.32 from 1.16 because it is the initial amount. Then divide what you get from that (0.84) by .21. You're gonna get .04- but that's not the answer because you have to add the initial ounce that is worth $0.32. So The answer is B
4 0
2 years ago
Read 2 more answers
If I was asked to think of a number and multiply it by 2, I could
Anna007 [38]
7(X+3) is the answer your welcome
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2 years ago
The area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of
Tpy6a [65]

Step-by-step explanation:

Let the width=x

Length =6x-4

As we know that in a rectangle

{\boxed{\sf Area=LB}}

  • Substitute the values

\hookrightarrow\sf x (6x-4)=20

\hookrightarrow\sf 6x^2-4x=20

\hookrightarrow\sf 6x^2-4x-20=0

  • Here a=6, b=-4, c=-20.
  • use quadratic formula

\hookrightarrow\sf x=\dfrac {1}{3}+\dfrac {1}{3}\sqrt {31} \quad or \quad \dfrac {1}{3}+\dfrac {-1}{3}\sqrt {31}

8 0
2 years ago
What is the product of 3.4 × 10−14 and 1.8 × 10^28?
DENIUS [597]
None of the answer matches the correct ans
(3.4×10-14)(1.8×10^28)
20(1.8×10^28)
3.6×10^29
8 0
3 years ago
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