F(x)=2x^2+6x−1 when x=4
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Answer:
Step-by-step explanation:
(A) The vertices of the trapezoid KLMN are K(1, 3) , L(3, 1) , M(3, 0) , and N(1, −2)
Now, KL= =\sqrt{8}[/tex]
LM=
MN=
NK=
Now, as KL and MN are equal, therefore, KLMN is an isosceles trapezoid.
(B) Since m∠XWY=47°, therefore ∠XWZ=47+47=94° and ∠ZYW=18°, therefore ∠XYZ=36°( as diagonals bisect the angles)
In ΔXWO,
∠XWO+∠WXO+∠WOX=180°(Angle sum property)
∠WXO=43°
Also, from ΔXOY,
∠OXY=72° using the angle sum property.
Therefore, ∠WXY=43+72=115°
Now, sum of all the angles of a quadrilateral is equal to 360°, therefore
∠WXY+∠XYZ+∠YZW+∠ZWX=360°
115°+36°+∠YZW+94°=360°
∠YZW=115°
Therefore,∠WZY=115°
(C) Since, AB and CD are the two parallel lines as the slope of both the sides are equal.
LetM be the mid point of AB, therefore M=
=
Also, let N be the mid point of DC, therefore,
N=
=
Now, length of the mid segment MN=
(D)Given: Kite PQRS, TS=6cm and TP=8cm
Then, From triangle TSP, we have
Base of the exponential equation should be (-1).
And finally the product or result should also be a negative number.
Let us take a variable for n natural numbers.
(Note: All positive whole numbers are called natural numbers that is 1,2,3,4,5,....).
In order to get the expression, we need to find the expession for odd natural numbers.
We know,
The expession for odd natural numbers is given by = 2n-1.
Where n= 1,2,3,4,5...
If we have an odd exponent of a negative number, it always gives a negative number.
We got, base = -1 ( a negative number) and
exponent = (2n-1) ........... expression for odd number.
Therefore, we could write final exponential expression that would give a negative for all natural numbers.