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kifflom [539]
3 years ago
12

Please help with this question

Mathematics
1 answer:
Marat540 [252]3 years ago
7 0
5 (1+2) .................
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Help me with this please and thank you!! :)
Ann [662]

Answer:

Step-by-step explanation:

  • A \cap C denotes the set of elements in both A and C, which is \{20, 24, 28\}.
  • B^{C} denotes the complement of set B, which is the set of all elements that are in the universal set that are not in set B. In this case, this set is \{3, 4, 5, 6, 8, 11, 13, 16, 17, 19, 20, 22, 23, 24, 25, 26, 27, 28\}
7 0
1 year ago
NEED HELP!
Citrus2011 [14]

Answer:

Michelle, because she was only 5 off, while Jae was 8 off

8 0
3 years ago
Rewrite the function in vertex form,y = (a - h)² + k, and identify the coordinates of the vertex and equation of axis of symmetr
Illusion [34]

Answer:

Rewrite the function in vertex form,y = (a - h)² + k, and identify the coordinates of the vertex and equation of axis of symmetry.Show Work y = -3x² - 24x - 50

Step-by-step explanation:

5 0
3 years ago
If mBDE = 125 what is mGDF? A) 35. B) 45. C) 55. D) 65
joja [24]
A supplmentary angle = 180°

∠BDE and ∠BDF are vertical angles, and so are congruent.

∠BDF = 125°, because ∠BDF ≅ ∠BDE.

∠CDA ≅ ∠EDF

∠CDA = 90°


<span>line BJ </span> is angle bisector of ∠CDA. ∠CDB is 1/2 of ∠CDA

∠CDA = 90°

∠CDB = 90/2
∠CDB = 45°

∠GDF is a vertical angle of ∠CDB, and it's measurement will be the same as ∠CDB.

∠GDF ≅ ∠CDB
∠CDB = 45°
∠GDF  = 45°


∠GDF  = 45° should be your answer

hope this helps
7 0
4 years ago
Read 2 more answers
Analyze the asymptotes of the function.
koban [17]

Answer:

vertical asymptote at x=-1

horizontal asymptote at y=0

Step-by-step explanation:

y=\frac{1}{x+1}

To find vertical asymptote we set the denominator =0 and solve for x

x+1=0 (subtract 1 from both sides)

x=-1

So, vertical asymptote at x=-1

To find horizontal asymptote we look at  the degree of both numerator and denominator

there is no variable at the numerator , so degree of numerator =0

degree of denominator =1

When the degree of numerator is less than the degree of denominator

then horizontal asymptote at y=0

5 0
3 years ago
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