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3 years ago

Please help with this question

Mathematics

1 answer:

Marat540 [252]3 years ago

7 0

5 (1+2) .................

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Find the additive inverse of 9/10 need help

frosja888 [35]

The Additive inverse only works when you add a to its oppositie leaving a sum of 0

For example, says 5 represents a.

5 + b = 0

B, is 5's additive inverse: -5

The reciprocal of 9/10, however, is 10/9

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3 years ago

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HEL ASAP PLEASEThe dimensions of a square with side measurements of 4 inches are doubled. What happens to the area of the square

Llana [10]

Answer:

The area is multiplied by 4

Step-by-step explanation:

4x4=16 (area 1)

4(x2)x4(x2)=64 (area 2 (with the measurements doubled)

64/16=4

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4 years ago

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Which of the following options results in a graph that shows exponential growth?

poizon [28]

Answer:

$f(x)=0.7(5)^x$

Step-by-step explanation:

$\text{Exponential function: }y=a\cdot b^x$

It is two types of function.

Exponential Growth: If function increase as value of x increase.

In this case, a>0 and b>1

Exponential decay: If function decrease as value of x increase.

In this case, a>0 and 0<b<1

We need to choose exponential growth function.

$\text{Exponential Growth function: }f(x)=0.7(5)^x$

Here a=0.75>0 and b=5>1

Therefore, This function is exponential growth.

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3 years ago

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Diego can type 140 in 4 minutes

oksano4ka [1.4K]

Answer:

11 min and 525 words

Step-by-step explanation:

I put 140 words/ 4 mins and simplified it to 35 words /1 min

Doing so i plug in what was given and used cross multiply and divid :D

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3 years ago

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What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)

Pachacha [2.7K]

Answer:

The third option listed: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

$7\sqrt[3]{2x} -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x} -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x} -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}$

And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:

$7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}$

Therefore this is the simplified radical expression: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

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3 years ago