<h3>Given</h3>
- room height is x feet
- room length is 3x feet
- room width is 3x feet
- a door 3 ft wide by 7 ft tall
<h3>Find</h3>
- The net area of the wall, excluding the door
<h3>Solution</h3>
The area of the wall, including the door, is the room perimeter multiplied by the height of the room. The room perimeter is the sum of the lengths of the four walls.
... gross wall area = (3x +3x +3x +3x)·x = 12x²
The area of the door is the product of its height and width.
... door area = (7 t)×(3 ft) = 21 ft²
Then the net wall area, exclusive of the door is ...
... net wall area = gross wall area - door area
... net wall area = 12x² -21 . . . . square feet
Answer:
8,640
Step-by-step explanation:
EASY PERIOD
Answer:
x >1/5
Step-by-step explanation:
5x-1 >0
Add 1 to each side
5x-1+1 >0+1
5x >1
Divide each side by x
5x/5 >1/5
x >1/5
Answer: 2
Step-by-step explanation:
The volume of the solid created upon dilation bythe scale factor of 3 is 5832 units³.
<h3>What is the volume of the dilated solid?</h3>
An image is dilated if the dimensions of the image is resized in a way that does not change the shape of the image. When an image is dilated, it is made larger.
Dimensions of the dilataed solid = 6 x 3 = 18
Volume = 18³ = 5832 units³
To learn more about dilation, please check: brainly.com/question/3457976
