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3 years ago

Can y'all help me with math I hate it

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

7 0

Answer:

1st one

Step-by-step explanation:

antoniya [11.8K]3 years ago

6 0

Answer:

Step-by-step explanation:

the first one

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If m1=9 what is the measure of 5

ikadub [295]

Ndbdbsb s sbsbsbsbsbsgs

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3 years ago

Find the length of the missing side

inn [45]

<h3>Answer: 9</h3>

================================================

Work Shown:

a = unknown = leg #1

b = 12 = leg #2

c = 15 = hypotenuse

Plug those values into the pythagorean theorem and solve for 'a'

a^2 + b^2 = c^2

a^2 + (12)^2 = (15)^2 .... substitution

a^2 + 144 = 225

a^2 = 225 - 144 ... subtracting 144 from both sides

a^2 = 81

a = sqrt(81) .... applying square root to both sides

a = 9

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3 years ago

If 4 pounds of potatoes is 3 dollars, how many dollars is 1 pound of potatoes?

jarptica [38.1K]

Answer: $1.33

Step-by-step explanation:

4 divided by 3

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3 years ago

10 points 8' 5" − 3' 10"

crimeas [40]

Answer:

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8 0

3 years ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago