Each two digit number has two numbers (duh!). Let's allow the tens digit to be x and the units digit to be y. Tens digit is 3 less than the units digit: x = y-3 Original number is 6 more than 4 times the sum of the digits: 10x+y-6 = 4x + 4y This gives us simultaneous equations!First let's clear the mess: 1. x= y-32. 6x-3y=6 Substitute 1 into 2: 6(y-3) -3y =66y - 18 - 3y = 6
3y = 24y = 8 Our units digit is 8 Substitute y= 8 into 1. x = y - 3x = 5 Our tens digit is 5 Therefore, our number is 58
Answer:
Step-by-step explanation:
t=(-2.74 + sqrt(2.74^(2)-4*-4.9*(-10))) / -2*-4.9
t=(-2.74 + sqrt(7.5076-4*+49))/9.8
t=(-2.74 + sqrt(7.5076+45))/9.8
t=(-2.74 + sqrt(52.5076))/9.8
t=(-2.74/9.8)+(sqrt(52.5076))/9.8
this is simplest form, next will be rounded answers
t=0.45981763305
Answer: $2.50
for rounding to the tenths, look at the hundredths place and if it is more than 5 round up :)
Let's try plugging in some negative numbers. Let's do x=-1. 5+-1=4. So we know that if we put in a negative number for x, then n will be positive. But what if we do a number greater than -5, because 5+-5=0. So let's try x=-6. So 5+(-6)=-1. Hmm. So here it is. We know that any number under -5 will be positive and any number above -5 will be negative.
Answer:
The answer is B
Step-by-step explanation:
hope that helps
