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saveliy_v [14]
3 years ago
10

Jean runs 8 mi and then rides 11 mi on her bicycle on a biathlon. She rides 9 mph faster than she runs. If the total time for he

r to complete the race is 1.5 hr, determines her speed running and her speed riding her bicycle.
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Let Jean's speed while running = x mph

Then Jean's speed while riding will be = x+9 mph

Distance covered by running = 8 miles

Distance covered by riding = 11 miles

Total time taken to complete the race = 1.5 hours

As, time=\frac{distance}{speed}

So, time for running= \frac{8}{x}

And time for riding= \frac{11}{x+9}

Equation becomes:

\frac{8}{x}+\frac{11}{x+9}=1.5

Now, multiply every term by 2x(x+9) to clear denominators:  

16(x+9)+22x=3x(x+9)

Simplifying it we get

3x^{2}-11x-144=0

Solve the quadratic equation using formula

x= \frac{-b+\sqrt{b^{2}-4ac }}{2a}

putting a=3 , b= -11, c= -144

we get (x - 9)(3x + 16) = 0

where x=9 and x=\frac{-16}{3}

Neglect the negative answer as speed cannot be negative, so x = 9 mph

Hence, Jean's running speed is 9 mph and riding speed is x+9 = 9+9 = 18 mph

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