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Marizza181 [45]
3 years ago
5

Given: x - 6 ≤ 1. Choose the solution set.

Mathematics
1 answer:
Gemiola [76]3 years ago
8 0

Answer:

x<7

Step-by-step explanation:

See image below:)

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Simply cross multiply and simplify to get a = 11

Hope this helped!! xx
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What is the square root of 196?
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The square root of 196 is 14
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Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

\lim_{x \to 2} f(x) = 1

\lim_{x \to 2} g(x) = -4

\lim_{x \to 2} h(x) = 0

a) Applying properties of limits

\lim_{x \to 2} f(x) + 5g(x) =  \lim_{x \to 2} f(x) + 5  \lim_{x \to 2} g(x) = 1 + 5*-4 = -19

b) Applying properties of limits

\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64

c) Applying properties of limits

\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1

d) Applying properties of limits

\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16

e) Applying properties of limits

\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0

f) Applying properties of limits

\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0

3 0
3 years ago
PLEASE HELP! WILL GIVE BRAINLIEST!
irinina [24]

Answer:

1: y intercept = 5

2: y interpcept = -2

3: y intercept = -3

Step-by-step explanation:

So for the 1st and 3rd ones (the graphs), all you have to do is find which y matches the x value of 0

The 2nd one is a bit harder. I’ll explain it the best I can

So in the y section, you see that -4 goes to -3 when the x is raised by 1. There for everytime the x raises by 1, so does the y. That means when x = 0, the y = -2

3 0
3 years ago
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Sarihas to read a book for English class by the end of the week.She wants to read at least 200 pages in the first 5days of the w
zzz [600]
200/5 = 40...she should read at least 40 per day to reach her goal
6 0
3 years ago
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