2 years ago

Factorize Зpq - 5р – 2p^2q

Mathematics

1 answer:

NeTakaya2 years ago

6 0

Answer: p x (3q - 5 - 2pq)

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If sec theta = - √30 / 3, find cos theta.<br> if sin(-theta) = -0.97, find cos (π/2 - theta).

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3 years ago

What is the sum of the answers to the eqation?<br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20%2B%205%2

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Step-by-step explanation:

$x^{2}$ - 6x +5 = 0

$x^{2}$ - 6x + 9 -9 +5 = 0

[ $x^{2}$ - 6x + 9] - 4 =0

$(x -3)^{2}$ -4 = 0

$(x -3)^{2}$ = 4

(x-3) = $\sqrt{4}$ or (x-3) = - $\sqrt{4}$

(x-3) = 2 or (x-3) = -2

x = 5 or x = 1

therefore, sum of these solutions is 5+1 = 6

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Factorize Зpq - 5р – 2p^2q​

Factorize Зpq - 5р – 2p^2q