Answer:
First question is 4,000
Second question is 2000
Step-by-step explanation:
You look at the point at which the graph lines meet and that is how you find you constant of proportionally.
Answer:
22.5 cm^2
Step-by-step explanation:
Amount of paper is going to be measured in area, so we want the surface area of the cone. Since it is a cub it doesn't have a base, so we don't need to count it.
Area of the cone without the base, or what is called the lateral area is pi*r*s where r is the radius and s is the slant height. and of course radius is d/2 where d is the diameter. so let's plug it in. We know diameter is 6 and slant height is 7.5
SA = pi * r * s
SA = pi * d/2 * s
SA = pi * 6/2 * 7.5
SA = 22.5 cm^2
So you will need 22.5 square centimeters of paper.
Answer:
scale factor = 2
Step-by-step explanation:
Determine the ratio of corresponding sides, image to original
scale factor =
= 2
Answer:
51.60% probability that a randomly selected adult has an IQ between 86 and 114.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the probability that a randomly selected adult has an IQ between 86 and 114.
Pvalue of Z when X = 114 subtracted by the pvalue of Z when X = 86. So
X = 114



has a pvalue of 0.7580
X = 86



has a pvalue of 0.2420
0.7580 - 0.2420 = 0.5160
51.60% probability that a randomly selected adult has an IQ between 86 and 114.
<span>g(x) = 6(4)x, Section A is from x = 0 to x = 1. Your "6(4)x" needs to be written as
</span><span>g(x) = 6(4)^x, where the " ^ " indicates exponentiation.
The average rate of change of g(x) from x= 0 to x=1 is:
6(4)^1 - 6(4)^0 24 - 6
a.r.c. = ----------------------- = ----------- = 18 (answer)
1-0 1
Now do the same thing for x = 1 to x = 2.</span>