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Answer:
The distance is<u> 4.726 </u>
Step-by-step explanation:
we need to find the distance from the point to the line
Given:- point (-1,-2,1) and line ; x=4+4t, y=3+t, z=6-t .
used formula
Let point P be (-1,-2,1)
using value t=0 and t=1
The point Q (4 , 3, 6) and R ( 8, 4, 5)
Let a be the vector from Q to R : a = < 8 - 4, 4 - 3, 5 - 6 > = < 4, 1, -1 >
Let b be the vector from Q to P: b = < -1 - 4, -2 - 3, 1 - 6> = < -5, -5, -5 >
The cross product of a and b is:
= -6i+15j-15k
The distance is :
≈4.726
Therefore, the distance is<u> 4.726 </u>
Explanation
where x is the number of days since the start of the job
and f(x) is the rate of change
Step 1
a)find the total expenditure if the job takes 12 days
so, as x represents the number of days, just replace and calculate
let x= 12
so
a) 51.1
Step 2
now, let's find the total spent on the job from the 10 to 20th day
a) find the x value ( number of days since the job started)
x= 20 days-10dys= 10
so
x= 10